Answer:
44.1 x 10^-2
Step-by-step explanation:
Since one grain
= 7 x 10^-5
6300kg = 7 x 10^-5 x 6300
Put 6300 in standard form
7 x 10^-5 x 6.3 x 10^3
Multiply the whole numbers and add the exponents
7 x 6.3 x 10^-5 + 3
44.1 x 10^-2
There are 44.1 x 10^-2 grains of sand in 6300kg
Answer:
Average rate of change = 20.2
Rate of change at the left endpoint : f' (5) = 4t = 20
Rate of change at the right endpoint : f' (5.1) = 4*5.1 = 20.4
Step-by-step explanation:
The average rate of change of the function
F(t) = 2t^2 - 1 , [ 5,5.1 ]
solution
=
= [ 2 ( 26.01 - 25 ) / 0.1 ]
= 2.02 / 0.1 = 20.2
Rate of change at the left endpoint : f' (5) = 4t = 20
Rate of change at the right endpoint : f' (5.1) = 4*5.1 = 20.4
a. Length of the fence around the field = perimeter of quarter circle = 892.7 ft.
b. The area of the outfield is about 39,584 sq. ft..
<h3>What is the Perimeter of a Quarter Circle?</h3>
Perimeter of circle = 2πr
Perimeter of a quarter circle = 2r + 1/4(2πr).
a. The length of the fence around the field = perimeter of the quarter circle fence
= 2r + 1/4(2πr).
r = 250 ft
Plug in the value
The length of the fence around the field = 2(250) + 1/4(2 × π × 250)
= 892.7 ft.
b. Size of the outfield = area of the full field (quarter circle) - area of the infield (cicle)
= 1/4(πR²) - πr²
R = radius of the full field = 250 ft
r = radius of the infield = 110/2 = 55 ft
Plug in the values
Size of the outfield = 1/4(π × 250²) - π × 55²
= 49,087 - 9,503
= 39,584 sq. ft.
Learn more about perimeter of quarter circle on:
brainly.com/question/15976233
Answer:
No
Step-by-step explanation:
Neither 4 or 7 is a solution to both equations
The correct answer is b
a thanks and a brainliest would be appreciated :)