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Amiraneli [1.4K]
2 years ago
12

PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS PLS

Mathematics
1 answer:
kirill [66]2 years ago
4 0
The answer should be (6,-1)

Explanation:

Focus on point A since it's asking for that. Then, shift it down vertically -8.

This means you are shifting A down 8 units.

Then they ask for a reflection across the y-axis. The y-axis is the vertical line in the middle, so to do this transformation, just change the x-value of where A is to the opposite.
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a bricklayer needs to order 6300kg of building sand.one grain of this sand weighs 7x10^-5. how many grains of sand are there in
gavmur [86]

Answer:

44.1 x 10^-2

Step-by-step explanation:

Since one grain

= 7 x 10^-5

6300kg = 7 x 10^-5 x 6300

Put 6300 in standard form

7 x 10^-5 x 6.3 x 10^3

Multiply the whole numbers and add the exponents

7 x 6.3 x 10^-5 + 3

44.1 x 10^-2

There are 44.1 x 10^-2 grains of sand in 6300kg

5 0
3 years ago
Find the average rate of change of the function over the given interval.
Minchanka [31]

Answer:

Average rate of change = 20.2

Rate of change at the left endpoint :   f' (5) = 4t = 20

Rate of change at the right  endpoint : f' (5.1) = 4*5.1 = 20.4

Step-by-step explanation:

The average rate of change of the function

F(t) = 2t^2 - 1 ,  [ 5,5.1 ]

solution

\frac{f(5.1)-f(5)}{5.1 - 5} = \frac{2*(5.1)^2-1-(2*5^2-1)}{0.1}   = [ 2 ( 26.01 - 25 ) / 0.1 ]

= 2.02 / 0.1 = 20.2

Rate of change at the left endpoint :   f' (5) = 4t = 20

Rate of change at the right  endpoint : f' (5.1) = 4*5.1 = 20.4

6 0
3 years ago
3. Here is a diagram of a softball field:
Crank

a. Length of the fence around the field = perimeter of quarter circle = 892.7 ft.

b. The area of the outfield is about 39,584 sq. ft..

<h3>What is the Perimeter of a Quarter Circle?</h3>

Perimeter of circle = 2πr

Perimeter of a quarter circle = 2r + 1/4(2πr).

a. The length of the fence around the field = perimeter of the quarter circle fence

= 2r + 1/4(2πr).

r = 250 ft

Plug in the value

The length of the fence around the field = 2(250) + 1/4(2 × π × 250)

= 892.7 ft.

b. Size of the outfield = area of the full field (quarter circle) - area of the infield (cicle)

= 1/4(πR²) - πr²

R = radius of the full field = 250 ft

r = radius of the infield = 110/2 = 55 ft

Plug in the values

Size of the outfield = 1/4(π × 250²) - π × 55²

= 49,087 - 9,503

= 39,584 sq. ft.

Learn more about perimeter of quarter circle on:

brainly.com/question/15976233

4 0
2 years ago
Is (4, 7) a solution to the system of equations? Explain your answer.
Angelina_Jolie [31]

Answer:

No

Step-by-step explanation:

Neither 4 or 7 is a solution to both equations

4 0
3 years ago
Select the table that represents a linear function.
nexus9112 [7]
The correct answer is b




a thanks and a brainliest would be appreciated :)


4 0
3 years ago
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