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2 years ago

How far can a train travel in 75 minutes, if it is going 40 mph?

2 answers:

7 0

50 miles, because it is going 60 minutes (1 hour) and that's 40, adding one fourth of 60 (which is 15) and one fourth of 40 (which is 10) it would have to be 50 miles.

Anni [7]2 years ago

4 0

Hey there! :D

We know that there are 60 minutes in a hour.

The car travels for 75 minutes.

75 minutes= 1 hour and 15 minutes.

1*40= 40

60/15= 4

We know that 15 minutes of driving is a quarter of an hour.

40/4= 10

40+10= 50

The car drove 50 miles.

I hope this helps!
~kaikers

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MATH QUESTION!! WILL MARK BRAINLIEST!! PAST DUE HELP ASAP!!!

monitta

Answer:

Proof below

Step-by-step explanation:

Right Triangles

In any right triangle, i.e., where one of its internal angles is 90°, some interesting relations stand. One of the most-used is Pythagora's Theorem.

In a right triangle with shorter sides a and b, and longest side c, called the hypotenuse, the following equation is satisfied:

$c^2=a^2+b^2$

The image provided in the question shows a line passing through points A(0,4) and B(3,0) that forms a right triangle with both axes.

The origin is marked as C(0,0) and the point M is the midpoint of the segment AB. We have to prove.

$CM=\frac{1}{2}AB$

First, find the coordinates of the midpoint M(xm,ym):

$\displaystyle x_m=\frac{0+3}{2}=1.5$

$\displaystyle y_m=\frac{4+0}{2}=2$

Thus, the midpoint is M( 1.5 , 2 )

Calculate the distance CM:

$CM=\sqrt{(1.5-0)^2+(2-0)^2}$

$CM=\sqrt{2.25+4}=\sqrt{6.25}=2.5$

CM=2.5

Now find the distance AB:

$AB=\sqrt{(3-0)^2+(4-0)^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}$

AB=5

AB/2=2.5

It's proven CM is half of AB

3 0

2 years ago

Es urgente necesito ayuda

zalisa [80]

ANSWER

a)56
b)134
c)27
d)141

5 0

2 years ago

Estimate the solution to the system of equations 7x−y=7 x+2y=6 i need help

Yanka [14]

Answer:

(4/3, 7/3)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients
Coordinates (x, y)
Solving systems of equations of using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

7x - y = 7

x + 2y = 6

Step 2: Rewrite Systems

Equation: x + 2y = 6

[Subtraction Property of Equality] Subtract 2y on both sides: x = 6 - 2y

Step 3: Redefine Systems

7x - y = 7

x = 6 - 2y

Step 4: Solve for y

Substitution

Substitute in x: 7(6 - 2y) - y = 7
Distribute 7: 42 - 14y - y = 7
Combine like terms: 42 - 15y = 7
[Subtraction Property of Equality] Subtract 42 on both sides: -15y = -35
[Division Property of Equality] Divide -15 on both sides: y = 7/3

Step 5: Solve for x

Define original equation: x + 2y = 6
Substitute in y: x + 2(7/3) = 6
Multiply: x + 14/3 = 6
[Subtraction Property of Equality] Subtract 14/3 on both sides: x = 4/3

7 0

2 years ago

What is the slope of a line that passes through (-3,5) and (4,3)?

AnnyKZ [126]

to find a slope you subtract the y value of the 2nd point from the y value of the 1st point then you devide that by the difference of the x value of the 2nd point subtracted from the x value of the 1st point. so 5-3 devided by -3-4, 5-3=2, -3-4=-7. so m = 2/-7 is your slope. the slope is usually represented with the letter m.

5 0

3 years ago

Geometry question, need some help :)

kodGreya [7K]

Answer:

Links are blurry please type (:

Step-by-step explanation:

8 0

3 years ago