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Hitman42 [59]
3 years ago
12

I could use some help

Mathematics
2 answers:
lorasvet [3.4K]3 years ago
7 0

Answer:

ok hear me out its C

Step-by-step explanation:

dalvyx [7]3 years ago
4 0
Option A, it’s the base times the height
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Help me with this please :)))))
BigorU [14]

Answer:

8.2

Step-by-step explanation:

if EG is 13, thats the total minus EF which is 4.8 so it equals 8.2

3 0
3 years ago
A car can be rented for $60 per week plus $0.40 per mile. How many miles can be driven if you have at most $300 to spend for wee
Step2247 [10]

Answer: 600 Miles

Step-by-step explanation:

We start off with $300.

We have to spend $60 to rent the car.

300 - 60 = $240

The remaining $240 can be spent on miles.

$240/0.40 = 600 Miles

6 0
3 years ago
Each month, Miss Patrick spends $60 on transportation to work, and earns $24.50 per hour.Each month, Mr. Shah spends $150 on lab
Semmy [17]

Answer:

3 hours for miss patrick 5 hours for mr shah

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
If 2.2 pounds = 1 kilogram and Mary weighs 120 pounds, how much does she weigh in <br> kilograms?
Strike441 [17]

Answer:

54.4311

Step-by-step explanation:

divide the mass value by 2.205 (unit of conversion) :)

5 0
3 years ago
Read 2 more answers
Consider randomly selecting a student at a large university. Let A be the event that the selected student has a Visa card, let B
wariber [46]

Answer:

a. 0.76

b. 0.23

c. 0.5

d. p(B/A) is the probability that given that a student has a visa card, they also have a master card

p(A/B) is the probability that given a student has a master card, they also have a visa card

e. 0.35

f. 0.31

Step-by-step explanation:

a. p(AUBUC)= P(A)+P(B)+P(C)-P(AnB)-P(AnC)-P(BnC)+P(AnBnC)

                    =0.6+0.4+0.2-0.3-0.11-0.1+0.07= 0.76

b. P(AnBnC')= P(AnB)-P(AnBnC)

                    =0.3-0.07= 0.23

c. P(B/A)= P(AnB)/P(A)

             =0.3/O.6= 0.5

e. P((AnB)/C))= P((AnB)nC)/P(C)

                     =P(AnBnC)/P(C)

                     =0.07/0.2= 0.35

f. P((AUB)/C)= P((AUB)nC)/P(C)

                    =(P(AnC) U P(BnC))/P(C)

                     =(0.11+0.1)/0.2

                     =0.21/0.2 = 0.31

7 0
3 years ago
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