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Luba_88 [7]
3 years ago
9

***TOP SAYS BAND AND PLAY INSTRUMENT AND NOT IN BAND AND PLAY INSTRUMENT***** A survey asked 50 students if they play an instrum

ent and if they are in band.
1. 25 students play an instrument
2. 20 students are in band
3. 30 students are not in band
WHICH TABLE SHOWS THESE DATA CORRECTLY ENTERED IN A TWO-WAY FREQUENCY TABLE??? PLEASE HELP

Mathematics
2 answers:
sergey [27]3 years ago
8 0

Answer:

Option B.

Step-by-step explanation:

Given that a survey asked 50 students if they play an instrument and if they are in band.  

1. 25 students play an instrument  

2. 20 students are in band  

3. 30 students are not in band

This gives that Option B has the correct table.

svp [43]3 years ago
6 0

Answer B shows the correct information. If you look at the totals of the tables, B shows that 30 aren't in a band, 20 are in a band, and 25 play an instrument.

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[ - 4 , 4 ) ∪ ( 4 , ∞ )

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be.

solve x - 4 = 0 ⇒ x = 4 ( is a vertical asymptote )

There is a zero when the numerator equals zero.

x + 4 = 0 ⇒ x = - 4 ( is a zero )

domain is [-4 , 4 ) ∪ ( 4 , ∞ )




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4 years ago
Find the missing side length.
zysi [14]

Answer:

the answer is in the picture

7 0
3 years ago
Please help I don't understand!
Citrus2011 [14]

Answer:

48

Step-by-step explanation:

Here, the sides are in proportion.

⇒ \frac{24}{k} = \frac{32}{64}

⇒ \frac{24}{k} = \frac{1}{2}

⇒ k = 24 × 2

⇒ k = 48

5 0
2 years ago
Find c. Determine it from the choices below.
Kobotan [32]

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12 centimeters

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3 0
3 years ago
Using the data in the table, which statement is true?
horsena [70]

Answer:  Choice C.  mean > median

================================================

Explanation:

Multiply each measure with their corresponding frequency.

  • 8*1 = 8
  • 10*3 = 30
  • 14*2 = 28

Add up those products: 8+30+28 = 66

Then divide by the total frequency n = 1+3+2 = 6 to get 66/6 = 11 as the mean.

mean = 11

----------------

Since we have n = 6 values in this list, this means the median is between slot n/2 = 6/2 = 3 and slot 4.

Note how that places us in the middle row because 1+3 = 4 encapsulates both of those slots mentioned. So the median is 10.

Or you could list out the values in roster notation {8, 10, 10, 10, 14, 14} to see that {10,10} occupy the middle most slots. So the median is (10+10)/2 = 20/2 = 10.

median = 10

-----------------

The mode is simply the most frequent value. The table shows that mode = 10 since it occurs 3 times, compared to 8 showing up 1 time and 14 showing up twice.

-----------------

We have the following summary

  • mean = 11
  • median = 10
  • mode = 10

With that in mind, let's go through the answer choices.

  1. We can see that mean < mode is false, since it should be mean > median, so cross choice A off the list.
  2. mean = median is also false, so choice B is crossed off as well.
  3. mean > median is true since 11 > 10 is true. Choice C is the answer. Note how this being true directly contradicts choice B, which is another reason to see why choice B is false.
  4. median > mode is false because 10 > 10 is false. It should be median = mode. Choice D is crossed off the list.
4 0
3 years ago
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