Hello from MrBillDoesMath!
Answer:
Domain: x >=0 for both cases
Discussion:
Assuming we are dealing with real valued functions, the domain of
y = x^(1/2) +4
is the set of all "x" such that x>= 0 (so we are taking the square root of a positive, or zero, real number)
The domain of x^(1/2) +6 -7 is the same as for the last function and for the same reason.
Thank you,
MrB
Step-by-step explanation:
Start by finding (fog)(x)
To find this function, substitute x=
x−1
4
That is g(x) into f(x)
⇒(f∘g)(x)=(
x−1
4
)
2
−2(
x−1
4
)+5
=
(x−1)
2
16
−
x−1
8
+5
Now substitute x=3
⇒(f∘g)(3)=
(3−1)
2
16
−
3−1
8
+5
=
4
16
−
2
8
+5=4−4+5=5.
Hope it helps:)
The graph y=|x|-4 is obtained from the graph y=|x| dy <span>moving down 4 units the graph y=|x| along the y-axis (see, if x=0, then for y=|x|, y=0 and for y=|x|-4, y=-4).
</span>
These two graphs have the same form.
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Answer:
-17
Step-by-step explanation:
4.5*6=27
so -44++27
