<u>Answer:</u>
Standard form of a line passing through (-2, 4) and having slope of -1/7 is x + 7y = 26
<u>Solution:</u>
Given that we need to determine standard form of a line that goes through (-2 , 4) and slope of the line is -1/7
Standard form of line passing through point ( a , b ) and having slope m is given by
(y – b) = m ( x – a) --------(1)
In our case given point is ( -2 , 4 ) and slope is -1/7 that means
a = -2 , b = 4 , m = -(1/7)
On substituting given value of a , b and m is equation (1) we get


=> 7( y - 4 ) = -x – 2
=> 7y + x = -2 + 28
=> x + 7y = 26
Hence standard form of a line passing through (-2,4) and having slope of –(1/7) is x + 7y = 26
Initial value is the value of y where x = 0 (y-intercept).
You are already given that line contains point (0, 5). The y-coordinate is 5 therefore answer is C.
Please mark Brainliest
Answer:
2.05 inches
Step-by-step explanation:
V = 4/3 x πr³
36=4πr³/3
36x3= 4πr³
108= 4πr³
108/4 = πr³
27= πr^3
27/π =r³
r=
![\sqrt[3]{27 \div \pi}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B27%20%5Cdiv%20%5Cpi%7D%20)
r= 2.048in
round off to 2.05in
<u>PROOF</u>
V = 4÷3 x πr³
V= 4/3 x π(2.05)³
V=4/3 x π8.6
V=4×π×8.6/3
V=108/3
V=36in³
Therefore: radius= <u>2.05 inches</u>