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dolphi86 [110]
3 years ago
7

We can describe 15x-10 as an expression We would describe 9x+5=32 as an

Mathematics
1 answer:
AlekseyPX3 years ago
6 0

Answer: Equation

Step-by-step explanation: because it has an equal sign. I think that’s what this question means.

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If earl runs 25 meters in 10 seconds how many meters does earl run per second?
Veseljchak [2.6K]
2.5 meters per second
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3 years ago
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Simplify the expression by combining like terms2a + 3b + 5 + 10 + 4b + 6b
Anastaziya [24]

Expression:

2a+3b+5+10+4b+6a

We can add just the terms that are similar, as follows:

=(2a+6a)+(3b+4b)+(5+10)

Simplifying:

=8a+7b+15

Answer: B.

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1 year ago
Two trains leave the station at the same time, one heading east and the other west. The eastbound train travels at 95 miles per
alisha [4.7K]

Answer:

It will take 1.6 hours for the two trains to be 336 miles apart.

Step by step explanation:

Given that:

Speed of eastbound train = 95 miles per hour

Speed of westbound train = 115 miles per hour

Combined speed = 95+115 = 210 miles

Distance = 336 miles

Speed = \frac{Distance}{Time}\\\\210 = \frac{336}{Time}\\\\Time = \frac{336}{210}\\\\Time = 1.6\ hours

Hence,

It will take 1.6 hours for the two trains to be 336 miles apart.

3 0
3 years ago
A computer assembling company receives 24% of parts from supplier X, 36% of partsfrom supplier Y, and the remaining 40% of parts
Ivan

Answer:

thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)

Step-by-step explanation:

denoting A= a piece is defective , Bi = a piece is defective from the i-th supplier and Ci= choosing a piece from the the i-th supplier

then

P(A)= ∑ P(Bi)*P(C) with i from 1 to 3

P(A)= ∑ 5/100 * 24/100 + 10/100 * 36/100 + 6/100 * 40/100 = 9/125

from the theorem of Bayes

P(Cz/A)= P(Cz∩A)/P(A)

where

P(Cz/A) = probability of choosing a piece from Z , given that a defective part was obtained

P(Cz∩A)= probability of choosing a piece from Z that is defective = P(Bz) = 6/100

therefore

P(Cz/A)= P(Cz∩A)/P(A) = P(Bz)/P(A)= 6/100/(9/125) = 5/6 (83.33%)

thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)

8 0
3 years ago
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Please answer this only for 35 points
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Answer:

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