Answer:
I think the answer is 0.3 in 0.4
We presume your cost function is
c(p) = 124p/((10 +p)(100 -p))
This can be rewritten as
c(p) = (124/11)*(10/(100 -p) -1/(10 +p))
The average value of this function over the interval [50, 55] is given by the integral
This evaluates to
(-124/55)*(ln(65/60)+10ln(45/50)) ≈ 2.19494
The average cost of removal of 50-55% of pollutants is about
$2.19 hundred thousand = $219,000
Answer:
hope it helps ya.
please give me brainliest
I belive the unit rate per goal is 5.7
Answer:38.26 because 2+38=40
40-1.74 =38.26