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Over [174]
4 years ago
5

Given f(x)= 4x^2-5, evaluate f(-2)

Mathematics
1 answer:
jek_recluse [69]4 years ago
8 0
F(-2)=4(-2)²-5
=4*4-5
=11

..................
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Pluto's distance P(t)P(t)P, left parenthesis, t, right parenthesis (in billions of kilometers) from the sun as a function of tim
Xelga [282]

Answer: P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

Step-by-step explanation: A motion repeating itself in a fixed time period is a periodic motion and can be modeled by the functions:

y = A.sin(B.t - C) + D or y = Acos(B.t - C) + D

where:

A is amplitude A=|A|

B is related to the period by: T = \frac{2.\pi}{B}

C is the phase shift or horizontal shift: \frac{C}{B}

D is the vertical shift

In this question, the motion of Pluto is modeled by a sine function and doesn't have phase shift, C = 0.

<u>Amplitude</u>:

a = \frac{largest - smallest}{2}

At t=0, Pluto is the farthest from the sun, a distance 6.9 billions km away. At t=66, it is closest to the star, P(66) = 4.4 billions km. Then:

a = \frac{6.9-4.4}{2}

a = 1.25

<u>b</u>

A time period for Pluto is T=66 years:

66 = \frac{2.\pi}{b}

b = \frac{\pi}{33}

<u>Vertical</u> <u>Shift</u>

It can be calculated as:

d = \frac{largest+smallest}{2}

d = \frac{6.9+4.4}{2}

d = 5.65

Knowing a, b and d, substitute in the equivalent positions and find P(t).

P(t) = a.sin(b.t) + d

P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

The Pluto's distance from the sun as a function of time is

P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

8 0
3 years ago
a truck and its load weigh 22,800 pound. if the load weight 12,400 pounds more than the truck, how many does the truck weight?
alexandr1967 [171]
10,400 pounds I think
5 0
4 years ago
Please help anybody hm​
Ghella [55]

Answer:

The answer is 1

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What are the domain and range of the absolute value parent function?
lozanna [386]

Answer:

The domain is all real numbers and the range is non-negative real numbers

(y ≥ 0) ⇒ answer B

Step-by-step explanation:

* Lets revise the parent function of the absolute value

- The absolute value or modulus |x| of a real number x is the

  non-negative value of x

- The absolute value of a number means the magnitude of the number

  without regard to its sign

- The parent function of the absolute value is f(x) = IxI

∵ The domain of the function is all the values of x which make the

  function defined

∵ In the function f(x) = IxI, x can be any number

∴ The domain of the f(x) is any real number

∴ The domain is (-∞ , ∞) or {x : x ∈ R}

∵ The range is the set of values of y that corresponding with the

   domain

∵ f(x) = IxI is non-negative value

∴ f(x) ≥ 0

∵ f(x) = y

∴ y ≥ 0

∴ The range is the set of real numbers greater than or equal zero

∴ The range is [0 , ∞) or {y : y ≥ 0}

* The true statement is: The domain is all real numbers and the range is

  non-negative real numbers (y ≥ 0)

8 0
3 years ago
Please Hurry its for a test
Kitty [74]
I would but I can’t see the picture I don’t know why... what is the question please type it ,thank you
4 0
3 years ago
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