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liubo4ka [24]
3 years ago
5

Circle theorem help

Mathematics
1 answer:
mojhsa [17]3 years ago
6 0
I hope this helps you

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Solve for x by using log. Rounded to hundredth. <br><br> <img src="https://tex.z-dn.net/?f=4%5E%7B2x-5%7D%20%3D6%5E%7B-x%2B1%7D"
wel

Answer: x=1.91

Step-by-step explanation:

Given the expression 4^{2x-5} =6^{-x+1}, apply logarithm to both sides. Then:

log(4)^{2x-5} =log(6)^{-x+1}

Remembert that according the the properties of logarithms:

log(a)^n=nlog(a)

Then:

(2x-5)log(4)=(-x+1)log(6)

Appy distributive property and solve for "x":

2xlog(4)-5log(4)=-xlog(6)+log(6)\\2xlog(4)+xlog(6)=log(6)+5log(4)\\x(2log(4)+log(6))=log(6)+5log(4)\\\\x=\frac{log(6)+5log(4)}{2log(4)+log(6)}\\\\x=1.91

6 0
4 years ago
Read 2 more answers
Your teacher gives you a number cube with numbers 1-6 on its faces. You are asked to state a theoretical probability model for r
butalik [34]

The missing part of the question is show in bold format.

Your teacher gives you a number cube with numbers 1-6 on its faces. You are asked to state a theoretical probability model for rolling it

once. Your probability model shows a probable outcome of 1/6 for each of the numbers on the cube, 1 chance for all any of the 6 numbers.

You roll it 500 times and get the following data:

Outcome 1 2 3 4 5 6

Frequency 77 92 75 90 76 90

Exercises 1–2

1. If the equality model was correct, about how many of each outcome

would you expect to see if the cube is rolled 500 times

2. Based on the data from the 500 rolls, how often were odd numbers observed? How often were even numbers observed?

Answer:

Step-by-step explanation:

1.

If the equally likely model was correct,  about how many of each outcome

would you expect to see if the cube is rolled 500 times.

The probability of rolling any of the numbers from 1 to 6 is  p(1/6)

The number of each of the outcomes expected to be seen in 500 rolls of the number cube is np

= 500 * \frac{1}{6}  \\ \\ = \frac{500}{6} \\ \\  = 83.333 \\ \\ \approx 83

2.  From the given data in the roll;

The odd numbers 1, 3 and 5, were obtained at  77, 75 and 76 times respectively.

Thus, the total number of times odd number were rolled = 77 + 75 + 76 = 228

Probability of an odd number turning up = \frac{ number \ of  \ required  \ outcome}{ total \  number  \ of  \ possible \ outcome}

= \frac{228}{500}

= 0.456

= 45.6%

The even numbers, 2, 4 and 6, were obtained 92, 90 and 90 times respectively.

The total number of times even number were rolled = 92 + 90 + 90 = 272

Probability of an even number turning up  = \frac{ number \ of  \ required  \ outcome}{ total \  number  \ of  \ possible \ outcome}

= \frac{272}{500}

= 0.544

= 54.4%

4 0
3 years ago
Is x=2 a solution to the equation below? <br> 4(x-1)-3(x-2)=-8
Sonbull [250]

Answer:

No

Step-by-step explanation:

To find out if 2 is a solution, replace all the x's with 2.

4(2 - 1) - 3(2 - 2) =8

4(1) - 3(0) = 8

4 - 0 = 8

4 = 8

Nope!  False!  2 is not a solution.

7 0
3 years ago
Students painted 1/2 the wall in the gym with 3 colors. Each color takes up the same amount of space on the wall. What fraction
irinina [24]
1/2 divided by 3 is 1/6

Hope this helps :D
3 0
3 years ago
How many quarts are equoqelant to 14 liters
svetlana [45]
Answers is 14.794 us liquid quarts
3 0
3 years ago
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