Answer:
option (c) 8 years
Explanation:
Data provided in the question:
Cost of the machine = $240,000
Useful life = 10 years
Salvage value = 0
Net income = $6,000 each year
Now,
Using the straight-line method of depreciation
Annual depreciation = [ Cost - Salvage value ] ÷ Useful life
= [ $240,000 - 0 ] ÷ 10
= $24,000
Thus,
Cash flow = $6,000 + $24,000
= $30,000
Therefore,
The payback period = ( Cost ) ÷ ( Cash flow )
= $240,000 ÷ $30,000
= 8 years
Hence,
the correct answer is option (c) 8 years
Answer:
7.5 Years
Explanation:
The computation of the payback period of the given machine is shown below:
<u>Year Initial outflow Cash flow Cumulative cash flow</u>
(52000)
1 10,000 10,000
2 10,000 20,000
3 10,000 30,000
4 8,000 38,000
5 8,000 46,000
6 2,000 48,000
7 2,000 50,000
8 4,000 54000
9 4,000 58000
10 4,000 62000
Now the Payback period is
= Completed years+ required cash ÷ annual cash inflow
= 7 years + 2000 ÷ 4000
= 7.5 Years
Answer:
4
Explanation:
4) go shopping for new clothes. you choose to get an hour of exercise. based on this what is the opportunity cost of your choice
<u>Solution and Explanation:</u>
- the total sales of calendars is as follows:
7200 multiply with $5 each = $36000
- In order to find out the profit, the toal of sales is to be subtarcted with costs. The given sales is $36000, costs is $19183
Thus, the total profit = $16817
95% of 10080 canot be taken in order to find out the correct number. 5% enrollment growth, is as follows:
10080 = 1.05 multiply "x"
thus, calculating x = 9600
- The number of studnets are 9600 in the last semester out of which 7200 bought calendar. 7200 divide 9600 = 75.0 percent sales penetration.
What poster are you referring to? There’s nothing there but the question
