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Nata [24]
3 years ago
7

What is 4/y+2=10/5y?

Mathematics
1 answer:
kobusy [5.1K]3 years ago
3 0
Y^1=-1,y^2=2 ^=square root
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Walter's family plays a quick game together every night after dinner. Walter draws names out of a hat to determine which kind of
Harlamova29_29 [7]

Answer:1st 2/3 2nd 1/3 3rd 1/9

Step-by-step explanation:

4 0
3 years ago
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A small regional carrier accepted 23 reservations for a particular flight with 20 seats. 14 reservations went to regular custome
MrRissso [65]

Answer:

- The probability that overbooking occurs means that all 8 non-regular customers arrived for the flight. Each of them has a 56% probability of arriving and they arrive independently so we get that  

P(8 arrive) = (0.56)^8 = 0.00967

- Let's do part c before part b. For this, we want an exact booking, which means that exactly 7 of the 8 non-regular customers arrive for the flight. Suppose we align these 8 people in a row. Take the scenario that the 1st person didn't arrive and the remaining 7 did. That odds of that happening would be (1-.56)*(.56)^7.

Now take the scenario that the second person didn't arrive and the remaining 7 did. The odds would be  

(0.56)(1-0.56)(0.56)^6 = (1-.56)*(.56)^7. You can run through every scenario that way and see that each time the odds are the same. There are a total of 8 different scenarios since we can choose 1 person (the non-arriver) from 8 people in eight different ways (combination).  

So the overall probability of an exact booking would be [(1-.56)*(.56)^7] * 8 = 0.06079

- The probability that the flight has one or more empty seats is the same as the probability that the flight is NOT exactly booked NOR is it overbooked. Formally,  

P(at least 1 empty seat) = 1 - P(-1 or 0 empty seats)  

= 1 - P(overbooked) - P(exactly booked)

= 1 - 0.00967 - 0.06079  

= 0.9295.

Note that, the chance of being both overbooked and exactly booked is zero, so we don't have to worry about that.

Hope that helps!

Have a great day :P

7 0
3 years ago
Use the pythagoren theorem to solve x
defon
Well the equation is (A^2)+(B^2)=(C^2)

A= x
B= 2x
C will always be the longest side because it is the Hypotenuse = 25

So if you plug in those numbers into the equation...

(x^2) + (2x^2) = (25^2)

x^2 + 4x^2 = 625

Combine like terms

5x^2 = 625

Divide by five to both sides

x^2 = 125

Then Square root,

x = sqrt(125)

x = sqrt(25* 5)

x = 5sqrt(5)
3 0
3 years ago
PLEASE ANSWER ASAP FOR BRAINLEST!!!!!!!!!!!!!!
Tom [10]

Answer:

You have to divide the total sales by 8 percent. 32,000/ 0.8 =40,000

So your answer is 40,000.

Step-by-step explanation:

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3 years ago
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Find the product of all positive divisors of 288.
irinina [24]

Answer:

<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>1</em><em>.</em><em>5</em><em>1</em><em>4</em><em>5</em><em>7</em><em>1</em><em>8</em><em>9</em><em>4</em><em>×</em><em>1</em><em>0</em><em>^</em><em>2</em><em>1</em><em>.</em>

Step-by-step explanation:

<em>Here</em><em>, </em><em> </em><em>the</em><em> </em><em>divisors</em><em> </em><em>of</em><em> </em><em>2</em><em>8</em><em>8</em><em> </em><em>are</em><em>,</em>

<em>1</em><em>,</em><em>2</em><em>,</em><em>3</em><em>,</em><em>4</em><em>,</em><em>6</em><em>,</em><em>8</em><em>,</em><em>9</em><em>,</em><em>1</em><em>2</em><em>,</em><em>1</em><em>6</em><em>,</em><em>1</em><em>8</em><em>,</em><em>2</em><em>4</em><em>,</em><em>3</em><em>2</em><em>,</em><em>3</em><em>6</em><em>,</em><em>4</em><em>8</em><em>,</em><em>7</em><em>2</em><em>,</em><em>9</em><em>6</em><em>,</em><em>1</em><em>4</em><em>4</em><em>,</em><em>2</em><em>8</em><em>8</em><em>.</em>

<em>now</em><em>,</em><em> </em><em>their</em><em> </em><em>product</em><em> </em><em>=</em><em>1</em><em>×</em><em>2</em><em>×</em><em>3</em><em>×</em><em>4</em><em>×</em><em>6</em><em>×</em><em>8</em><em>×</em><em>9</em><em>×</em><em>1</em><em>2</em><em>×</em><em>1</em><em>6</em><em>×</em><em>1</em><em>8</em><em>×</em><em>2</em><em>4</em><em>×</em><em>3</em><em>2</em><em>×</em><em>3</em><em>6</em><em>×</em><em>4</em><em>8</em><em>×</em><em>7</em><em>2</em><em>×</em><em>9</em><em>6</em><em>×</em><em>1</em><em>4</em><em>4</em><em>×</em><em>2</em><em>8</em><em>8</em>

<em>=</em><em>1</em><em>.</em><em>5</em><em>1</em><em>4</em><em>5</em><em>7</em><em>1</em><em>8</em><em>9</em><em>4</em><em>×</em><em>1</em><em>0</em><em>^</em><em>2</em><em>1</em><em>.</em>

<em>is</em><em> </em><em>answer</em><em>. </em>

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

6 0
3 years ago
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