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kondaur [170]
3 years ago
10

Write the ratio as a fraction in lowest terms. 3 to 3 1/5

Mathematics
1 answer:
julia-pushkina [17]3 years ago
7 0
Use mathpapa maybe it will help
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What system of inequalities would you use to solve the problem below?
Flauer [41]

Answer:

answer D

Step-by-step explanation:

Hello

you cannot work more than 22 hours a week so

s + c <= 22

you get paid $8 an hour for swimming lessons and $10 a hour for cashier so you will get

8s + 10c and you make to get at least $190 so

8s + 10c >= 190

the correct answer is the last one

hope this helps

7 0
3 years ago
Which set of ordered pairs do NOT represent a function?
Rainbow [258]

Answer:

Every input can have only one output. But an output can have multiple inputs. Basically an x coordinate can have the same y coordinate as another ordered pair but not the same x coordinate. This is why d) does not represent a function.

Step-by-step explanation:

(4,-2)

(4,2)

4 is mentioned twice and every input( x value) can have only one output ( y-value)

7 0
2 years ago
Please help i will mark brainliest!​
GuDViN [60]

Answer:

Cluster Sampling

Step-by-step explanation:

I cant be 100% sure as i am not in statistics, but by definition cluster sampling is a probability sampling technique where researchers divide the population into multiple groups (clusters) for research (in this case its the phone book). Researchers then select random groups (three random pages) with a simple random or systematic random sampling technique for data collection and data analysis(interviews).

so that appears to be what is happening in this scenario.

6 0
3 years ago
(x^2y^-2)^3/yx^-4 please help
TiliK225 [7]
Hey is there a way you could send a photo of the equation
3 0
2 years ago
Solve the system of linear equations.
icang [17]

Answer: The set does not have a solution

Step-by-step explanation:

Adding Equations 1 & 3 we get 5x = 7. This gives x = 7/5

Putting this value of x in eq. 2 we get

-2y + 2z = -1-(7/5) or

2y - 2z = 12/5  or  5y - 5z = 6

Multiplying eq. 1 by 2  we get  

4x + 2y - 2z = 6

adding this with eq. 2 we get 5x = 5 or x = 1

As the common solution for x from equations 1&3 does not satisfy eq. 1&2 it comes out that the three equations do not have a common solution.

Same can be verified by using different sets of two equations also.

7 0
3 years ago
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