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AURORKA [14]
2 years ago
5

Solving inequalities?

Mathematics
1 answer:
Solnce55 [7]2 years ago
8 0

Answer:

i will try my best to find the answer of question if i can

Step-by-step explanation:

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Anybody Know This. ?
love history [14]

Answer:

The answerrrrrrrrrrr is (0,-2)

8 0
3 years ago
Read 2 more answers
Persuade Mr.Zorn whether the numbers 12, 16, and 20 make a right triangle or not. make sure to state reasons for and against you
TEA [102]

Answer:

They don’t 12+16+20= 48

12 x 16 x 20= 3840

Step-by-step explanation:

3 0
3 years ago
A press release describing the 1986 nonstop, round-the-world trip by the aircraft voyager including the following data:
adoni [48]

Answer:

a.) the average speed of the aircraft in miles per hour

115.76 miles/ hour

b.) the fuel consumption in miles per pound of fuel

(assume a density of 0.70 g/mL for the fuel.)

2.8 miles/Ib of fuel

Step-by-step explanation:

A press release describing the 1986 nonstop, round-the-world trip by the aircraft voyager including the following data:

flight distance: 25,012 miles

flight time: 9 days, 3 min., 44 seconds

fuel capacity: nearly 9000 lbs.

fuel remaining at the end of flight: 14 gal.

To the maximum number of significant figure permitted, calculate:

a.) the average speed of the aircraft in miles per hour

Step 1

We convert the time to hours

flight time: 9 days, 3 min., 44 seconds

1 day = 24 hours

9 days =

24 × 9

= 216 hours

60 mins = 1 hour

3 mins =

3/60 = 1/20 = 0.05 hours

1 hour = 60 minutes

1 minute = 60 seconds

1 hour = 60 × 60 = 3600 seconds

If 3600 seconds = 1 hour

44 seconds =

= 44/3600

= 0.0122222222 hours

Total number of hours spent = (216 + 0.05 + 0.0122222222) hours

= 216.06222222 hours

Speed = Distance/Time

= flight distance: 25,012 miles

Speed = 25,012 miles/ 216.06222222hours

= 115.76294895 miles/ hour

Approximately = 115.76 miles/ hour

b.) the fuel consumption in miles per pound of fuel

(assume a density of 0.70 g/mL for the fuel.)

Step 1

We determine how much fuel is used

We have 14 gallons of fuel left over

1 gallon = 3.785 litres

14 gallons =

Cross Multiply

14 gallons × 3.785 liters/1 gallon

= 52.9958 liters

Note that density of fuel =

0.70 g/ml

1 gram / millilitre = 1 kilogram / litre

Hence, 0.7g/ml = 0.7 kg/L

Hence,the mass of fuel left = 52.9958 liters * 0.7 = 37.09706kg

1 kilogram = 2.205 pounds

37.09706kg =

37.09706kg × 2.205 pounds

= 81.7990173 lbs

Since the full capacity = 9000 lbs

The fuel used = 9000 - 81.7990173 lbs

= 8918.2009827 lbs

Hence, fuel consumption is

Distance/ amount of fuel used

25012/8918.2009827 lbs = 2.8046015164 miles/lb of fuel

Approximately = 2.8 miles/Ib of fuel

7 0
3 years ago
Lu is making a quilt that is 20 squares wide and has 18 rows the border of the quilt is made by using each toy design equally as
mixer [17]

Answer:

The correct answer is two designs are used 12 times each and other four designs are used for 13 times each.

Step-by-step explanation:

Width of the quilt Lu is making is 18 rows of 20 squares each.

Thus the perimeter of the quilt is 20 + 20 + 18 + 18 = 76.

We can also say there are 76 square as the boundary which are to be bordered with toy designs.

Each square can hold 1 design of toy and there are 6 different designs of toys.

Thus number of times each design is used \frac{76}{6} = 12 \frac{4}{6}.

Thus there are two designs used 12 times each and other four designs are used for 13 times each.

3 0
3 years ago
Derek uses a 136 cm flat steel bar that weighs 4 kg to make rack in the garage. Determine the weight of a 170 cm steel bar
Bumek [7]

The weight of a 170 cm steel bar will be 5 Kg

Step-by-step explanation:

Derek uses a 136 cm flat steel bar that weighs 4 kg to make rack in the garage.

1 kg = 1000 gm

So the weight of 1 cm steel bar will be  \frac{4 }{136} kg

Weight of 1 cm bar = \frac{4000}{136} gm

Let the weight of a 170 cm steel bar will be \frac{4000 }{136} × 170 gm

⇒4000 × 1.25 gm

⇒ 5000 gm

⇒5 kg

Hence, the weight of a 170 cm steel bar will be 5 Kg

4 0
3 years ago
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