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hichkok12 [17]
3 years ago
15

How many athletes exercised more than 40 but less than 60 minutes

Mathematics
2 answers:
nika2105 [10]3 years ago
5 0

The <em><u>correct answer</u></em> is:

4.

Explanation:

The number 40 is written in this stem-and-leaf plot as 4|0.  60 is written as 6|0.  There are 4 leaves between these numbers; 5, 5, 5 and 5, with the stem of 4.  This means the numbers are 45, 45, 45 and 45.  There are only 4 between these two numbers.

BaLLatris [955]3 years ago
3 0
4.  When reading the stem and leaf plot the only values that fall between the range of  40 < x <60  is the 4 values of 45.  They are located at the tail end of the 4 stem after the zeros. The 40s and 60s are not counted because it is not mentioned equal to 40 or 60.
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A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a
zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}

Hence the answer is 0.1157

(ii) None is defective becomes

\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}

hence the answer is 0.4823

(iii) All are defective

\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}

(iv) At least one is defective

This is 1 - probability that none is defective

\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}

Hence the answer is 0.5177

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11 months ago
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daser333 [38]

Answer:

Step-by-step explanation:

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2 years ago
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hram777 [196]

Answer:

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Step-by-step explanation:

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3 years ago
Which of the following equations listed below has a radius of 3?
Evgesh-ka [11]

Answer:

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x^2 + y^2 + 12x - 20y+ 132 = 0

(x + 6)^2 - 36 + (y - 10)^2 - 100 = -132

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x^2 + y^2 + 12x - 20y + 55 = 0

will give a right hand side of -55 + 36 + 100 = 81  giving radius 9.

x^2 + y^2 - 12x+ 20y + 127 = 0

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Find the volume for the regular pyramid.<br><br><br><br> V =
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Answer:

What do you mean by that?

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