A ball bearing is shaped like a sphere and has a diameter of 2.5 centimetres. What is the volume contained inside the ball beari
2 answers:
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Answer: y = 4x-3
slope = 4, y intercept = -3
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m = 4 is the slope
is the point the line goes through
Using point slope form, we can say,
The equation is in slope intercept form y = mx+b
m = 4 = slope
b = -3 = y intercept
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As an alternative, you can use y = mx+b to get the same answer. We'll plug in m = 4 and (x,y) = (-2,-11) to solve for b
y = mx+b
-11 = 4(-2)+b
-11 = -8+b
-11+8 = -8+b+8
-3 = b
b = -3 we get the same y intercept value as above
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To check the answer, plug x = -2 into the equation. We should get y = -11
y = 4x-3
y = 4(-2)-3
y = -8-3
y = -11 we get the proper y value. The answer is confirmed.
Answer:
x ≈ 9.6
Step-by-step explanation:
Δ ABC is right with ∠ C = 90° ( angle between tangent and radius )
Using Pythagoras' identity in the right triangle
x² + 14² = 17²
x² + 196 = 289 ( subtract 196 from both sides )
x² = 93 ( take the square root of both sides )
x = ≈ 9.6 ( to the nearest tenth )