<span>Let us start with the plane flying east at a slower speed. Let us assume that its speed is x kilometers per hour. After 4 hours, it will have traveled 4*x = 4x kilometers.
Now let us calculate the speed of the plane flying west. It is faster by 75 kilometers per hour than the other plane. So its speed per hour is x+75 kilometers per hour. After 4 hours, it will have traveled 4( x+75) = 4x+300 kilometers. The total distance traveled by both the planes is 5460 kilometers. In other words, 4x+4x+300 =5460 kilometers.
Now simplify the equation:
8x + 300 = 5460
8x = 5460 - 300
8x = 5160
x = 5160/8 645.
x is the speed of the plane flying east. It is 645 kilometers.
x + 75 is the speed of the plane flying west. It is 645 + 75 =
720 kilometers.</span>
In three dimensions, the cross product of two vectors is defined as shown below

Then, solving the determinant

In our case,

Where we used the formula for AxB to calculate ixj.
Finally,

Thus, (i+j)x(ixj)=i-j
Answer:
1. 3x+3y=9 since it is a coinciding line.It is equivalent because all the terms are multiplied by 3 from the original equation.
2. x-4=3x+4
x=3x+8
-2x=8
x=-4
y=-4-4
y=-8
please mark me brainlyest <i cant spell it i think i spelled it wrong lol >
Answer:
12)
(9y +7)=(2y +98)( Because vertically opposite angle is always equal)
9y - 2y = 98-7
9y - 2y = 98-7
7y= 91
y =13
<em>ther</em><em>fore</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>1</em><em>3</em>
<em>(</em><em>9</em><em>y</em><em> </em><em>+</em><em> </em><em>7</em><em>)</em>
9*13+7
117+7
124
(2y +98)
2*13+98
26+98
124