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Alekssandra [29.7K]
3 years ago
15

|-6|+|3| I really don't get it do I simply find the sum our is it

Mathematics
2 answers:
Lemur [1.5K]3 years ago
5 0
9 because anything in the absolute value signs can't be negative, so it would be 6 + 3 = 9


MrMuchimi3 years ago
3 0
|a|=  \left\{\begin{array}{ccc}a&if\ a\geq0\\-a&if\ a < 0\end{array}\right\\\\|-3|=3\\|\ 0\ |=0\\|\ 6\ |=6\\|-100|=100\\\\\\|-6|+|\ 3\ |=6+3=9
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A number is decreased by seven. Then, the new number is multiplied by three to get an answer of -7 what is the original number
Aneli [31]

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5 0
3 years ago
A particular electronic component is produced at two plants for an electronics manufacturer. Plant A produces 70% of the compone
Vesna [10]

Answer:

If a component received by the manufacturer is defective, the probability that it was produced at plant A is 0.5385 = 53.85%.

Step-by-step explanation:

We use the Bayes Theorem to solve this question.

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Defective component

Event B: Produced at plant A.

Plant A produces 70% of the components used

This means that P(B) = 0.7

Among the components produced at plant A, the proportion of defective components is 1%.

This means that P(A|B) = 0.01

Probability of a defective component:

1% of 70%(defective at plant A)

2% of 100 - 70 = 30%(defective at plant B). So

P(A) = 0.01*0.7 + 0.02*0.3 = 0.013

If a component received by the manufacturer is defective, the probability that it was produced at plant A is

P(B|A) = \frac{0.7*0.01}{0.013} = 0.5385

If a component received by the manufacturer is defective, the probability that it was produced at plant A is 0.5385 = 53.85%.

4 0
3 years ago
ANSWER CORRECTLY TO BE MARK AS BRAINLIEST!!
Degger [83]

Answer:

5.5 ;)

Step-by-step explanation:

7 0
3 years ago
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