Let's say that the unknown value here is c. Although we are given two points on the line, it is only necessary to use one as there is only one unknown value, so let's say we choose the point (6, -12) and substitute this into the equation:
-12 = 1(6) - c
-12 - 6 = -c
-18 = -c
c = 18
Thus the equation for the line is y = 1x - 18
You said that (xy) = 16, and (x+y) = 4 .
From the second equation you can get [ x = 4 - y ],
then substitude that for 'x' in the first equation, and
finally, rearrange the first equation to read
<u>x² - 4x + 16 = 0</u>
Don't even try to factor that quadratic equation. Go straight
to the quadratic formula, and the two solutions you find are ...
<em>x = 2 + i 2√3</em>
and
<em>x = 2 - i 2√3</em> .
Those are the two number that do what you want.
There are no <u>real</u> numbers that can do it.
Answer:
0.0475 = 4.75% probability that a randomly selected complaint takes more than 15 minutes to be settled.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 10 minutes and a standard deviation of 3 minutes
This means that 
Find the probability that a randomly selected complaint takes more than 15 minutes to be settled.
This is 1 subtracted by the p-value of Z when X = 15, so:



has a p-value of 0.9525.
1 - 0.9525 = 0.0475.
0.0475 = 4.75% probability that a randomly selected complaint takes more than 15 minutes to be settled.
Answer: the operation can be said as x( 576-68)t-5= x
Step-by-step explanation:
You can see this because I am smart and just am