PLEASE ASAP !!!!! What is the value of x? A. 76° B. 56° C. 66° D. 46°

Sophia spent $27.16 on four sandwiches. If each sandwich cost the same amount, how much does one sandwich cost?

HACTEHA [7]

Answer:

6.79

Step-by-step explanation:

you just divide 27.16 (the cost) by 4 (how many sandwiches were purchased)

5 0

3 years ago

A television game show has 11 doors, of which the contestant must pick 3. Behind 3 of the doors are expensive cars, and behind

bezimeni [28]

For there to be 1 car, we consider two possible outcomes:

The first door opened has a car or the second door opened has a car.

P(1 car) = 2/6 x 4/5 + 4/6 x 2/5

P(1 car) = 8/15

For there to be no car in either door

P(no car) = 4/6 x 3/5

P(no car) = 2/5

Probability of at least one car is the sum of the probability of one car and probability of two cars:

P(2 cars) = 2/6 x 1/5

= 1/15

P(1 car) + P(2 cars) = 8/15 + 1/15

= 3/5

6 0

3 years ago

What is x in 2(x+20)=90

katovenus [111]

Answer:

25

Step-by-step explanation:

2(25+20)=90. 25 plus 20 is 45 and 45 times 2 is 90

6 0

3 years ago

Read 2 more answers

What is the function ?

Igoryamba

Answer:

Step-by-step explanation:

How many units u move

7 0

3 years ago

Consider the line integral Z C (sin x dx + cos y dy), where C consists of the top part of the circle x 2 + y 2 = 1 from (1, 0) t

pashok25 [27]

Direct computation:

Parameterize the top part of the circle $x^2+y^2=1$ by

$\vec r(t)=(x(t),y(t))=(\cos t,\sin t)$

with $0\le t\le\pi$ , and the line segment by

$\vec s(t)=(1-t)(-1,0)+t(2,-\pi)=(3t-1,-\pi t)$

with $0\le t\le1$ . Then

$\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)$

$=\displaystyle\int_0^\pi(-\sin t\sin(\cos t)+\cos t\cos(\sin t)\,\mathrm dt+\int_0^1(3\sin(3t-1)-\pi\cos(-\pi t))\,\mathrm dt$

$=0+(\cos1-\cos2)=\boxed{\cos1-\cos2}$

Using the fundamental theorem of calculus:

The integral can be written as

$\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)=\int_C\underbrace{(\sin x,\cos y)}_{\vec F}\cdot\underbrace{(\mathrm dx,\mathrm dy)}_{\vec r}$

If there happens to be a scalar function $f$ such that $\vec F=\nabla f$ , then $\vec F$ is conservative and the integral is path-independent, so we only need to worry about the value of $f$ at the path's endpoints.