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SpyIntel [72]
3 years ago
15

Five toppings for a pizza are available at Polina's Pizza. How many combinations of two different toppings are possible?

Mathematics
1 answer:
Rasek [7]3 years ago
8 0
Evaluate 
  
    C           This gives you the # of combinations possible from 5 choices taken 
5       2        2 at a time.  The answer is 10.  I used my calculator to find this.
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Can anyone please answer this question thankyou.<br>simplify 6√3-4√3+2 <br><br>​
Aleks [24]

Answer:

The answer for this question is <u><em>2√3 + 2.</em></u>

Step-by-step explanation:

<u><em>6√3 - 4√3 + 2</em></u>

<u><em>= ( 6 - 4 )√3 + 2</em></u>

<u><em>= 2√3 + 2 </em></u><em>  </em><u><em> ans...</em></u>

<u><em></em></u>

Hope its helpful :-)

If so, please mark me as brain-list :-)

5 0
1 year ago
Read 2 more answers
Consider the equation y = -2x + 5. Create a table of five ordered pairs that satisfy the equation. What is the y-intercept of th
Tatiana [17]

Answer: option d.

Step-by-step explanation:

To create a table of five ordered pairs that satisfy the equation, you need to give values to the variable "x" and substitute these into the function to find the corresponding value of "y":

For x=-2

y = -2(-2) + 5=9

For x=-1

y = -2(-1) + 5=7

For x=0

y = -2(0) + 5=5

For x=1

y = -2(1) + 5=3

For x=2

y = -2(2) + 5=1

Then, you can make the table:

<em><u>x</u></em><u>   </u><u>-2  -1  0  1  2</u>

<em><u>y   </u></em><u> </u><u>9  7  5  3  1</u>

To find the  x-intercept, substitute y=0 into the function and solve for "x". Then:

0 = -2x + 5\\\\x=\frac{-5}{-2}\\\\x=\frac{5}2}

This is: (\frac{5}{2}, 0)

To find the  y-intercept, substitute x=0 into the function and solve for "y". Then:

y= -2(0) + 5\\\\y=5

This is: (0,5)

6 0
3 years ago
Read 2 more answers
Express each of the following radios in the simplest form.
AURORKA [14]

Answer:

hope it helps man

eeeed

Step-by-step explanation:

edddd

4 0
2 years ago
What conclusion can you draw about angles of elevation for parasailing boats traveling at the same speed?
melamori03 [73]

Question:

A boat is travelling at 30 mph has  a 400 ft. tow line results in the height of the rider in the parasail above the water level of 300 ft.

a) Draw a labelled diagram of the situation

b) Determine the angle of elevation of the parasail rider

c) Parasailing boats traveling at the same speed will have the same angle of elevation

Answer:

a) Please find the attached drawing of the parasail boat created with MS Visio

b) The angle of elevation of the parasail rider from the boat is approximately 48.6°

Step-by-step explanation:

a) Please find the labelled diagram of the parasailing boat created with MS Visio

b) sing trigonometric ratios, we have;

sin(\theta) = \dfrac{Opposite \ leg \ length}{Hypotenuse \ length}

The opposite leg = The height of the parasail rider above water = 300 ft.

The hypotenuse = the length of the tow line = 400 ft.

θ = The angle of elevation of the parasail rider

\therefore sin(\theta) = \dfrac{300 \, ft.}{400 \, ft.} = 0.75

θ = Arctan(0.75) ≈ 48.6°

The angle of elevation above the horizontal of the parasail rider from the boat, θ ≈ 48.6°

c) From the construction of the drawing and the derivation of the angle of elevation given only the length of the tow line and the height given to the parasail rider by the speed of the both,

Parasailing boats traveling at the same speed, having the same length of tow line, will have the same angle of elevation, provided other factors that have an effect on the angle of elevation are the same

6 0
3 years ago
You're conducting a significance test for H0 : p = .35, Ha : p &lt; .35. In a sample of size 40, you identify a count of 11 succ
nordsb [41]

Answer: c. –1 and .1587

Step-by-step explanation:

As per given , we have

Null hypothesis : H_0 : p= 0.35

Alternative hypothesis :  H_1 : p< 0.35

Since Alternative hypothesis is left-tailed ,so the test must be a left tailed test .

Z -Test statistic for proportion = z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

, where p= population proportion

\hat{p} = sample proportions

n= Sample size.

Let x be the number of successes.

For n= 40 and x= 11

\hat{p}=\dfrac{x}{n}=\dfrac{11}{40}=0.275

Then ,  z=\dfrac{0.275-0.35}{\sqrt{\dfrac{0.35(1-0.35)}{40}}}

z=\dfrac{-0.075}{\sqrt{0.0056875}}

z=\dfrac{-0.075}{0.075415515645}

z=-0.99449031619\approx-1

By using z-table ,

P-value for left-tailed test = P(z<-1)= 1-P(z<1)    [∵ P(Z<-z)= 1-P(Z<z) ]

= 1-0.8413

=0.1587

Hence, the -score and P-value are  <u>–1 and 0.1587</u> .

So the correct option is c. –1 and .1587

8 0
3 years ago
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