The surface area of a regular triangular pyramid is 197.1 square meter. The slant height is 12. The area of the base is 35.1 squ
are meters. The base length is 9 meters. What is the height of the triangular base?
2 answers:
Answer:
h = 7.8
Step-by-step explanation:
A = 1/2*b*h
35.1 = 1/2*9*h . . . . dimensions apply to the base only
35.1*2/9 = h = 7.8 . . . m is the height of the triangular base.
Check:
The base is an equilateral triangle, so the height will be (9 m)*sin(60°) = 7.8 m.
_____
For the question asked, the surface area and slant height are irrelevant.
Answer:
2
Step-by-step explanation:
(12x9/2)3=162
197.1-162=35.1
(35.1x2/2)=35.1
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Step-by-step explanation:
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