The surface area of a regular triangular pyramid is 197.1 square meter. The slant height is 12. The area of the base is 35.1 squ
are meters. The base length is 9 meters. What is the height of the triangular base?
2 answers:
Answer:
h = 7.8
Step-by-step explanation:
A = 1/2*b*h
35.1 = 1/2*9*h . . . . dimensions apply to the base only
35.1*2/9 = h = 7.8 . . . m is the height of the triangular base.
Check:
The base is an equilateral triangle, so the height will be (9 m)*sin(60°) = 7.8 m.
_____
For the question asked, the surface area and slant height are irrelevant.
Answer:
2
Step-by-step explanation:
(12x9/2)3=162
197.1-162=35.1
(35.1x2/2)=35.1
You might be interested in
Answer:
uuh The a is equal to 16
Step-by-step explanation:
Answer:
<h2>x³ + 8x² - 3x - 24 = (x + 8)(x - √3)(x + √3)</h2>
Step-by-step explanation:

Yes! If there one one negative and one positive then the answer would've been negative!
Answer:
3y+3
Step-by-step explanation:
I hope this works
Answer:
Step-by-step explanation:
5t - 3 = 14
5t=14+3
5t=17
t=17/5
t=3.4