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lorasvet [3.4K]
3 years ago
5

The surface area of a regular triangular pyramid is 197.1 square meter. The slant height is 12. The area of the base is 35.1 squ

are meters. The base length is 9 meters. What is the height of the triangular base?
Mathematics
2 answers:
Gre4nikov [31]3 years ago
6 0

Answer:

h = 7.8

Step-by-step explanation:

A = 1/2*b*h

35.1 = 1/2*9*h . . . . dimensions apply to the base only

35.1*2/9 = h = 7.8 . . . m is the height of the triangular base.

Check:

The base is an equilateral triangle, so the height will be (9 m)*sin(60°) = 7.8 m.

_____

For the question asked, the surface area and slant height are irrelevant.

Leona [35]3 years ago
5 0

Answer:

2

Step-by-step explanation:

(12x9/2)3=162

197.1-162=35.1

(35.1x2/2)=35.1

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The level from each growth factors is an illustration of combination

There are 90 ways of combining one level from each growth factors

<h3>How to determine the number of combination</h3>

From the complete question (see attachment), we have the number of levels in each growth factor is:

  • Lighting = 3
  • Age = 5
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So, the number of combination (n) is:

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n = 90

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7 0
2 years ago
Suppose the number of radios in a household has a binomial distribution with parameters n=11 and p=40%. Find the probability of
Ivenika [448]

Answer:

Step-by-step explanation:

The formula for binomial distribution is expressed as

P(x=r) = nCr × q^(n-r) × p^r

From the information given,

n = 11

p = 40% = 40/100 = 0.4

q = 1 - 0.4 = 0.6

x represent the number of radios

a) P( x = 1) or P(x = 9)

P(x = 1) = 11C1 × 0.6^(11-1) × 0.4^1

P(x = 1) = 0.027

P(x = 9) = 11C9 × 0.6^(11-9) × 0.4^9

P(x = 9) = 0.0052

P( x = 1) or P(x = 9) = 0.027 + 0.0052 = 0.0322

b) P(x lesser than or equal to 7) = P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4) + P(x = 5) + P(x = 6)

P(x = 0) = 11C0 × 0.6^(11-0) × 0.4^0 = 0.004

P(x = 1) = 0.027

P(x = 2) = 11C2 × 0.6^(11-2) × 0.4^2 = 0.089

P(x = 3) = 11C3 × 0.6^(11-3) × 0.4^3 = 0.177

P(x = 4) = 11C4 × 0.6^(11-4) × 0.4^4 = 0.24

P(x = 5) = 11C5 × 0.6^(11-5) × 0.4^5 = 0.22

P(x = 6) = 11C6 × 0.6^(11-6) × 0.4^6 = 0.15

P(x = 7) = 11C7 × 0.6^(11-7) × 0.4^7 = 0.15

P(x lesser than or equal to 7) = 0.004 + 0.027 + 0.089 + 0.177 + 0.24 + 0.22 + 0.15 + 0.07 = 0.977

c) P(x greater than or equal to 5) = 1 - P(x lesser than or equal to 4) = 1 - (0.004 + 0.027 + 0.089 + 0.177 + 0.24) = 1 - 0.537 = 0.463

d) P(x lesser than 9) = P(x lesser than or equal to 7) + P(x = 8)

P(x = 8) = 11C8 × 0.6^(11-8) × 0.4^8 = 0.02

P(x lesser than 9) = 0.977 + 0.02 = 0.997

e. P(x greater than 7) = 1 - P(x lesser than or equal to 7) = 1 - 0.977 = 0.023

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Describe the graph showing the relationship between the weight of something in kilograms and its weight in pounds. Use the conve
rewona [7]

Answer:

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Explanation:

A constant conversion factor, such as 1 kg 2.2 lb, means that the two units are in direct proportion; thus the graph is a straight line that goes through the origin.

The conversion factor also gives the slope of the line.

Depending on which axis you choose for either unit the slope may be 2.2 pounds per kilogram, or 1/2.2 kilogram per pound.

When you use the y-axis for pounds and the x-axis for kilograms then the relationship is:

  • y = 2.2 x

In that case, the slope is 2.2 pounds per kilogram.

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