Answer:
The correct option is: A) sympatric speciation
Explanation:
Sympatric speciation is a type of geographic mode of speciation. It refers to the evolution of two or more than two new or descendant species from the existing common descent. The new species and the ancestral species all live in the same geographic area or location.
The common example of this speciation is insects like moths that become dependent on different plants belonging to the same geographical area.
Answer:
0.483
Explanation:
The given population is in Hardy-Weinberg equilibrium. If the gene has two alleles, the sum total of the frequencies of these two alleles will be one.
Therefore, the total of the frequency of allele B and frequency of allele b will be 1. f(B) + f(b)=1
If the frequency of allele "B" is 0.59, then the frequency of allele "b" will be=1-0.59= 0.41
The frequency of heterozygous genotype in the population= 2pq
p= frequency of the dominant allele
q= frequency of the recessive allele
So, 2pq= 2 x 0.59 x 0.41 = 0.483
The nurse should provide clean clothing as an option for the patient, and let them know they are willing to clean their clothes and give them right back. The nurse should assure the patient that she means no harm by taking their clothes; she/he is only going to wash them. They should also deny any delusions about the nurse taking the patient's clothing.
Hope this helps!
Mature DNA cells do NOT contain DNA.
If a lobster loses a claw, it is capable of growing a new one because of mitosis.
