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Yuri [45]
3 years ago
6

If black fur is dominant in rabbits, is it ever possible for two black fur rabbits to produce a white fur offspring?

Chemistry
1 answer:
tatyana61 [14]3 years ago
3 0

Answer:

No

Explanation:

It is not possible because the Black fur is the dominant gene and White fur is not therefor if both rabbits have black fur it is impossible for the offspring of the rabbits to have white fur.

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Which of these elements has an atom with the most stable outer electron configuration? * Cl Ca Ne Na
SashulF [63]

Answer:

Neon (Ne) has the most stable outer electron configuration because the outer electron is completely filled and it has octet structure

Explanation:

The configuration of these elements is as follows;

Cl₁₇ = 2, 8,7 (the outer electron is 7)

Ca₂₀ = 2,8,8,2 (the outer electron is 2)

Ne₁₀ = 2,8 (the outer electron is 8)

Na₁₁ = 2,8,1 (the outer electron is 1)

Based on the outer electron value above, Neon (Ne) has the most stable outer electron configuration because the outer electron is completely filled and it has octet structure.

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3 years ago
What is the concentration of a solution?​
Nimfa-mama [501]

The concentration of a substance is the quantity of solute present in a given quantity of solution.

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Which of the following is untrue concerning a reversible reaction?
Mars2501 [29]

The statement that is untrue concerning a reversible reaction is The reaction always spends equal time in the forward and reverse direction. The answer is letter B. The reset of the statements are true concerning the reversible reaction.

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Give the percent yield when 28.16 g of CO2 are formed from the reaction of 4.000 moles of C8H18 with 4.000 moles of O2.
ludmilkaskok [199]

Answer:

Percentage yield =  25%

Explanation:

Given data:

Moles of C₈H₁₈ = 4 mol

Moles of O₂ = 4 mol

Actual yield of CO₂ = 28.16 g

Percentage yield = ?

Solution:

Chemical equation:

2C₈H₁₈ + 25 O₂ → 16CO₂ + 18H₂O

Now we will compare the moles of CO₂ with O₂ and C₈H₁₈.

                 C₈H₁₈     :      CO₂

                     2        :       16

                     4        :       16/2×4=32 mol

                  O₂         :      CO₂

                    25        :      16

                     4         :       16/25×4=2.56 mol

Mass of CO₂:

Mass = number of moles× molar mass

Mass = 2.56 mol ×44 g/mol

Mass = 112.64 g

Percentage yield:

Percentage yield = Actual yield /theoretical yield × 100

Percentage yield = 28.16 g / 112.64 g× 100

Percentage yield = 0.25× 100

Percentage yield =  25%

5 0
3 years ago
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