The answer is 0.405 M/s
- (1/3) d[O2]/dt = 1/2 d[N2]/dt
- d[O2]/dt = 3/2 d[N2]/dt
- d[O2]/dt = 3/2 × 0.27
- d[O2]/dt = 0.405 mol L^(-1) s^(-1)
false
because science is an ever-growing subject we can never stop learning from it and expanding our knowledge.
(sorry that's the best that I can do)
The formula for GPE is PE=mgh, where “m” is the mass of the object, “g” is the acceleration due to gravity (~9.8 m/s^2 on Earth’s surface), and “h” is the height of the object from the ground. Therefore,
PE=mgh
PE=(6 kg)(9.8 m/s^2)(1 m)
PE=58.8 kg•m^2/s^2 or 58.8 Newtons
The GPE of the bowling ball under these conditions would be about 59 Newtons.
Hope this helps!
