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3 years ago

Please Help Assap!!!

Chemistry

1 answer:

amm18123 years ago

7 0

Answer:

A)distance = 0 and displacement = 0

B)distance = 10 meters and displacement = 0

D)distance = 10 meters and displacement = 10 meters

F)distance = 10 meters and displacement = 1 meter

In fact, displacement cannot be larger than distance, because distance is the total distance travelled in any direction, while displacement takes into account the direction. When the object moves only in one direction, distance and displacement are equal; however, if the motion of the object consists of several motions into more directions (like going back and forth), the distance travelled is always larger than the displacement. For this reason, choices C) and E) are wrong.

Explanation:

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A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the

baherus [9]

Answer: 1. $9.08\times 10^{-6}$ moles

2. 90 mg

Explanation:

$O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)$

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus $4.54 \times 10^{-6}$ moles of ozone is removed by = $\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6}$ moles of sodium iodide.

Thus $9.08\times 10^{-6}$ moles of sodium iodide are needed to remove $4.54\times 10^{-6}$ moles of $O_3$

2. $\text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles$

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by = $\frac{2}{1}\times 0.0003=0.0006$ moles of sodium iodide.

Mass of sodium iodide= $moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg$ (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of $O_3$ .

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2 years ago

Please help!

liberstina [14]

Answer:

To help determine what type of rock it is

Explanation:

Geologists can use information such as color, hardness, grain size, texture and other aspects of the rock to figure out the classification of a rock. for example, a light blue rock with no visible grain that is translucent and has a hardness of 9 is most likely going to be a saphire. hope this helps!!!!

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2 years ago

Read 2 more answers

What are the coefficients that would balance this equation _____NaOH+____H2CO3-Na2CO3+_____H2O

FromTheMoon [43]

I don’t see any equal signs to make it an equation. Am I missing something?

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2 years ago

What is the noble gas configurations for argon?

madreJ [45]

Answer:

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2 years ago

Three samples of the same metal are weighed and their masses are found to be 44.40 g, 40.58 g, and 38.35 g. The corresponding vo

lidiya [134]

The density of a material is the mass of the material per unit volume. Here the weight of the same metal is 44.40g, 40.58g and 38.35g having volume 4.8 mL, 4.7 mL and 4.2 mL respectively. Thus the density of the metal as per the given data are, $\frac{44.40}{4.8}$ = 9.25g/mL, $\frac{40.58}{4.7}$ = 8.634g/mL and $\frac{38.35}{4.2}$ = 9.130g/mL respectively.

The equation of the standard deviation is √{∑(x - $\frac{}{x}$ )÷N}

Now the mean of the density is {(9.25 + 8.634 + 9.130)/3} = 9.004 g/mL.

The difference of the density of the 1st metal sample (9.25-9.004) = 0.246 g/mL. Squaring the value = 0.060.

The difference of the density of the 2nd metal sample (9.004-8.634) =0.37 g/mL. Squaring the value = 0.136.

The difference of the density of the 3rd metal sample (9.130-9.004) = 0.126 g/mL. Squaring the value 0.015.

The total value of the squared digits = (0.060 + 0.136 + 0.015) = 0.211. By dividing the digit by 3 we get, 0.070. The standard deviation will be $\sqrt{0.070}=0.265$ . Thus the standard deviation of the density value is 0.265g/mL.

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2 years ago