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3 years ago

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Chemistry

1 answer:

amm18123 years ago

7 0

Answer:

A)distance = 0 and displacement = 0

B)distance = 10 meters and displacement = 0

D)distance = 10 meters and displacement = 10 meters

F)distance = 10 meters and displacement = 1 meter

In fact, displacement cannot be larger than distance, because distance is the total distance travelled in any direction, while displacement takes into account the direction. When the object moves only in one direction, distance and displacement are equal; however, if the motion of the object consists of several motions into more directions (like going back and forth), the distance travelled is always larger than the displacement. For this reason, choices C) and E) are wrong.

Explanation:

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The answer is- $SF_{6}$ is octahedral in electronic and molecular geometry with 6 Fluorine atoms bonded to central atom S.

Lewis structures are the diagrams in which the valence electrons of the atoms of a compound are arranged around the atoms showing the bonding between the atom and the lone pair of electrons existing in the molecule.

Determine the molecular geometry of $SF_{6}$ .

Valence Shell Electron Pair Repulsion theory is commonly known as VSEPR theory and it helps to predict the geometry of molecules.
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The Lewis structure of $SF_{6}$ is - (Image attached).
In the structure, the number of atoms bonded to central atom (S) = 6.
Number of non-bonding electron pairs on the central atom = 0 (as all the valence electrons are bonded to F).
Electronic geometry in case of 6 bond pairs is octahedral.
Molecular geometry us also octahedral with bond angles 90°.
Central atom is sp3d2 hybridised.
$SF_{6}$ is a non-polar molecule.

To learn more about Lewis structures visit:

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