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Maru [420]
3 years ago
15

Freezing and thawing water can cause a rock to break down into smaller pieces. Which part of the rock cycle is this an example o

f?
melting
weathering
subsidence
deposition
Chemistry
2 answers:
Juliette [100K]3 years ago
6 0

Answer:

deposition

Explanation:

Ap3x

zloy xaker [14]3 years ago
4 0

Answer:

Deposition

Explanation:

It’s breaking down the rock :]

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Chemical weathering takes place fastest in a _______ and _________ climate​
ser-zykov [4K]
Possibly wet and unstable
3 0
3 years ago
A 4.00-gram sample of sodium chloride was added to a beaker containing 40.0 mL 0.033 M lead(II)
melamori03 [73]
The answer is going to be 2.5
6 0
3 years ago
A series of six solutions was prepared at the given concentrations. Sample A B C D E F Concentration (mM) 50 100 150 200 300 400
ioda

Answer:

300 mM

Explanation:

In order to solve this problem we need to calculate the line of best fit for those experimental values. The absorbance values go in the Y-axis while the concentration goes in the X-axis. We can calculate the linear fit using Microsoft Excel using the LINEST function (alternatively you can write the Y data in one column and X data in another one, then use that data to create a dispersion graph and finally add the line of best fit and its formula).

The <u>formula for the line of best fit for this set of data is</u>:

  • y = 0.005 * x

So now we <u>calculate the value of </u><u><em>x</em></u><u> when </u><u><em>y</em></u><u> is 1.50</u>:

  • 1.50 = 0.005 * x
  • x = 300 mM

7 0
3 years ago
Question#31-32, I not sure and don’t know how to do,
LUCKY_DIMON [66]

Answer: 30. 7 moles SO3

31. 3 moles SO2 and 3 moles SO3

Explanation: To solve for this problem use the mole ratio of the substances involved in the reaction.

Solution for number 30:

3.5 moles O2 x 2 moles SO3 / 1 mole O2

= 7 moles SO3

31. 192 g SO2 x 1 mole SO2 / 64 g/ mol SO2

= 3 moles SO2

3 moles SO2 x 2 moles SO3 / 2 moles SO2

= 3 moles SO3

8 0
3 years ago
How many sig-figs in the following measurements?
DerKrebs [107]

Answer:

1.605cm = 4 significant figures

16.050cm = 4 significant figures

16.050cm = 4 significant figures

12 + 12.5 + 125 = 149.5 = 4 significant figures

1.62 × 10^3/2.8 × 10^-5 = 1620/0.000028 = 11 significant figures

4 0
3 years ago
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