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SOVA2 [1]
3 years ago
8

Question 5

Mathematics
1 answer:
kramer3 years ago
8 0

Answer:

The possible numbers that Kelley might have scored are:

1, 2, 3, 4, 5, 6, 7 and 8

Step-by-step explanation:

Please kindly see the attached file for more explanation

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50+24/(6x2) <br> Please solve and show work. Thank you.
stepladder [879]
<span>50+<span>24<span>6<span>x2

</span></span></span></span><span>=<span><span><span>300<span>x^2</span></span>+24/</span><span>6<span>x^2
the answer is </span></span></span></span><span>=<span><span><span>50<span>x^2</span></span>+4/</span><span>x^<span>2</span></span></span></span>
6 0
3 years ago
2 7/20 divided by 2/5 = ____
777dan777 [17]

Hi,

Solution:

Find Common Denominators,

2/5 = 8/20

2 7/20

Turn into improper fractions,

2 7/10 = 47/20

Divide,

47/20 ÷ 8/20 = 5.875/1 = 5 7/8

Answer,

5 7/8

8 0
3 years ago
Find point P that divides segments AB into a 2:3 ratio.
nasty-shy [4]
\bf ~~~~~~~~~~~~\textit{internal division of a line segment}&#10;\\\\\\&#10;A(-3,1)\qquad B(3,5)\qquad&#10;\qquad \stackrel{\textit{ratio from A to B}}{2:3}&#10;\\\\\\&#10;\cfrac{A\underline{P}}{\underline{P} B} = \cfrac{2}{3}\implies \cfrac{A}{B} = \cfrac{2}{3}\implies 3A=2B\implies 3(-3,1)=2(3,5)\\\\&#10;-------------------------------\\\\&#10;P=\left(\cfrac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \cfrac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)

\bf -------------------------------\\\\&#10;P=\left(\cfrac{(3\cdot -3)+(2\cdot 3)}{2+3}\quad ,\quad \cfrac{(3\cdot 1)+(2\cdot 5)}{2+3}\right)&#10;\\\\\\&#10;P=\left(\cfrac{-9+6}{5}~~,~~\cfrac{3+10}{5}  \right)\implies P=\left(-\frac{3}{5}~~,~~\frac{13}{5}  \right)
6 0
3 years ago
Determine if the statement is true or false. If a linear system has the same number of equations and variables, then it must hav
lutik1710 [3]

Answer:

False

Step-by-step explanation:

Consider the equations with the same number of equations and variables as shown below,

<u>Case 1</u>

                        x_{1} + x_{2} = 0\\x_{1} + x_{2} = 1

This equation has no solution because it is not possible to have two numbers that give a sum of 0 and 1 simultaneously.

<u>Case 2</u>

                       x_{1} + x_{2} = 1\\2x_{1} + 2x_{2} = 2

This equation has infinitely many possible solutions.

Therefore it is FALSE to say a linear system with the same number of equations and variables, must have a unique solution.

5 0
3 years ago
Equivalent Fractions
TEA [102]

Answer:

What is the question????

5 0
3 years ago
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