<span>50+<span>24<span>6<span>x2
</span></span></span></span><span>=<span><span><span>300<span>x^2</span></span>+24/</span><span>6<span>x^2
the answer is </span></span></span></span><span>=<span><span><span>50<span>x^2</span></span>+4/</span><span>x^<span>2</span></span></span></span>
Hi,
Solution:
Find Common Denominators,
2/5 = 8/20
2 7/20
Turn into improper fractions,
2 7/10 = 47/20
Divide,
47/20 ÷ 8/20 = 5.875/1 = 5 7/8
Answer,
5 7/8
Answer:
False
Step-by-step explanation:
Consider the equations with the same number of equations and variables as shown below,
<u>Case 1</u>

This equation has no solution because it is not possible to have two numbers that give a sum of 0 and 1 simultaneously.
<u>Case 2</u>

This equation has infinitely many possible solutions.
Therefore it is FALSE to say a linear system with the same number of equations and variables, must have a unique solution.