Answer:
<em>The probability that 10 or more students will live in campus housing is approximately 0.111%</em>
Step-by-step explanation:
<u>Binomial distribution formula:</u>
<em>If the probability of success is
, then the probability of
successes out of
trials will be:
</em>
26% of college students live in campus housing. So here, 
A random sample of 15 college students is selected. So, 
Now, "10 or more students" means 10 or 11 or 12 or 13 or 14 or 15 students. That means, 
Thus, the probability that 10 or more students will live in campus housing will be........
![[^1^5C_{10}(0.26)^1^0(1-0.26)^5]+[^1^5C_{11}(0.26)^1^1(1-0.26)^4]+[^1^5C_{12}(0.26)^1^2(1-0.26)^3]+[^1^5C_{13}(0.26)^1^3(1-0.26)^2]+[^1^5C_{14}(0.26)^1^4(1-0.26)^1]+[^1^5C_{15}(0.26)^1^5(1-0.26)^0]\\ \\ = 0.00094...+0.00015...+0.00001...+ 0.0000014...+ 0.000000071...+0.0000000016...\\ \\ =0.00111002... =0.111002...\% \approx 0.111\%](https://tex.z-dn.net/?f=%5B%5E1%5E5C_%7B10%7D%280.26%29%5E1%5E0%281-0.26%29%5E5%5D%2B%5B%5E1%5E5C_%7B11%7D%280.26%29%5E1%5E1%281-0.26%29%5E4%5D%2B%5B%5E1%5E5C_%7B12%7D%280.26%29%5E1%5E2%281-0.26%29%5E3%5D%2B%5B%5E1%5E5C_%7B13%7D%280.26%29%5E1%5E3%281-0.26%29%5E2%5D%2B%5B%5E1%5E5C_%7B14%7D%280.26%29%5E1%5E4%281-0.26%29%5E1%5D%2B%5B%5E1%5E5C_%7B15%7D%280.26%29%5E1%5E5%281-0.26%29%5E0%5D%5C%5C%20%5C%5C%20%3D%200.00094...%2B0.00015...%2B0.00001...%2B%200.0000014...%2B%200.000000071...%2B0.0000000016...%5C%5C%20%5C%5C%20%3D0.00111002...%20%3D0.111002...%5C%25%20%5Capprox%200.111%5C%25)
Answer:
turning it I think.........
Answer:
190
Step-by-step explanation:
57.5 x 2=115 so that is the arc for CE
then you add that to 55 to get 170
a circle is 360 so then you subtract 360 for 170