All categories

2 years ago

!!!!please need help on this asap

Mathematics

1 answer:

Musya8 [376]2 years ago

6 0

I believe after adding the x values and the degree values you would get x=10

You might be interested in

a right triangle is removed from a rectangle to create the shaded region shown below. find the area of the shaded region. be sur

ser-zykov [4K]

Answer:

Step-by-step explanation:

Objective: Find missing dimensions of the right triangle using the then subtract that area of the triangle from the rectangle's area.

Using the definition of a rectangle, the left vertical side measure is 7 and right vertical side is 6. So the missing legs of the triangle is 4 and 3.

Apply triangle formula, base x height divided by 2.

$\frac{4 \times 3}{2} = 6$

Area of rectangle is length x width so the area is

$7 \times 6 = 42$

Subtract 6 from 42.

$42 - 6 = 36$

3 0

2 years ago

What is the value is of x? A)0 B)25 C)4 D)7

iogann1982 [59]

We know that these two angles are equal to each other (There is the "congruent" sign) so we can set them equal to each other and solve for x

3x - 17 = 25 - 3x

(3x + 3x) - 17 = 25 + (-3x + 3x)

6x + (- 17 + 17) = 25 + 17

6x/6 = 42/6

x = 7

Hope this helped!

7 0

2 years ago

What is the center of the data?

satela [25.4K]

Answer:

$Median = 13$

Step-by-step explanation:

Given

See attachment for dot plot

Required

The center of data

This implies that, we calculate the median

From the attached plot,

$n = 13$ --- number of observation

So, the median is:

$Median = \frac{n + 1}{2}$

$Median = \frac{13 + 1}{2}$

$Median = \frac{14}{2}$

$Median = 7th$

The median is at the 7th position

At the 7th position, is 13

Hence:

$Median = 13$

5 0

2 years ago

Read 2 more answers

A potential energy function is given by U = A x3 + B x2 − C x + D . For positive parameters A, B, C, D this potential has two eq

Ivenika [448]

Answer:

7.8655

Step-by-step explanation:

Given the functionl

$U=Ax^3+Bx^2-cx+D$

Where,

$A=1.45J/m^3\\B=2.85J/m^2\\c= 1.7J/m\\D=0.6J$

We have, replacing,

$U=1.45x^3+2.85x^2-1.7x+0.6$

We need to derivate and verify for stable equilibrum that,

$\frac{d^2 U}{dx^2}>0$

Then,

$U'(x) = 4.32x^2+5.7x-1.7$

Roots in,

$x_1=-1.57008\\x_2=0.250636$

We obtain U"(x), then we have

$\frac{d^2U}{dx}=8.64x+5.7$

For $x=-1.57, U"(x)=-7.86549$ Unestable

For $x=0.250636 U"(x)=7.8655>0$ Stable

7 0

2 years ago

4^5 5^3 6^2 4^4 5^2 6

Nezavi [6.7K]

4^5 = 1024

5^3 = 125

6^2 = 36

4^4 = 256

5^2 = 25

3 0

1 year ago