Answer:

Step-by-step explanation:
Given
ID Card of 5 digits
Possibly Digits = {0,1...,9}
Required
Probability that a card has exact number 94213
First, we have o determine the total possible number of ID card numbers
Let the card number be represented by ABCDE
Given that repetition of digits is not allowed;
<em>A can be any of 10 digits</em>
<em>B can any of the remaining 9 digits</em>
<em>C can be any of the remaining 8 digits</em>
<em>D can be any of the remaining 7 digits</em>
<em>E can be any of the remaining 6 digits</em>
<em />
Total number of cards = 10 * 9 *8 * 7 * 6
Total = 30240
Provided that the card number is generated at random; each card number has the same probability of 
Hence, the probability of having 94213 is 
Answer:
I'm not sure but thank you and have a Merry Christmas
Answer:
(2h-3k)(m-n)
Step-by-step explanation:
factor by grouping, you can group the first two terms and the last two terms:
2h(m-n) + (-3k)(m-n)
there will be one factor in common, use that factor in combination with the factors that are not duplicated:
(2h-3k)(m-n)
There would be 1/12 of the cake left.