What is the area of the composite figure?

Do yall know 2-1 3/8

alex41 [277]

Answer:

It's 0.625

Step-by-step explanation:

3 0

3 years ago

Betty had 40$ in her pocket. She bought 12 identical bags of popcorn. Betty was left with $10 after buying the popcorn. What was

omeli [17]

Hey darling^^

Your answer is...

$2.50

~Hope I helped~

*Alanna*

8 0

3 years ago

The function f(x) is a cubic function and the zeros of f(x) are -3, -2, and 1. The y-intercept of f(x) is -24. Write the equatio

Serga [27]

Answer:

f(x) = 4x³+16x²+4x-24

Step-by-step explanation:

Factors are (x+3)(x+2)(x-1)

(x+3)(x²+2x-x-2)

(x+3)(x²+x-2)

x³+x²-2x+3x²+3x-6

x³+4x²+x-6

This could have been the function but the intetcept is 6 here.

So we'll take a miltiple of this one such that the intercept becomes-24

-24/-6 = 4

That multiple is 4

f(x) = 4(x³+4x²+x-6)

f(x) = 4x³+16x²+4x-24

7 0

3 years ago

In an attempt to escape a desert island, a castaway builds a raft and sets out to sea. The wind shifts a great deal during the d

nikdorinn [45]

Answer:

R = 7,34 km

Ф = 63,43° north of east

Step-by-step explanation:

Let´s analyze each movement and find its perpendicular components. Then, we are going to add the components along the x and y axes to get the resultant and finally to calculate its magnitude and direction.

To determine the perpendicular components, we will use right triangles trigonometrics ratios.

Please see images for each displacement in attached file.

Displacement A: 2.50 km and 45° north of west

Ax= AcosФ = 2.50cos45° = 1.77 km (neg. direction)

Ay= AsenФ = 2.50sen45° = 1.77 km (pos. direction)

Displacement B: 4.70 km and 60° south of east

Bx= BcosФ = 4.70cos60° = 2,35 km (pos. direction)

By= BsenФ = 4.70sen60° = 4,07 km (neg. direction)

Displacement C: 1.30 km and 25° south of west

Cx= CcosФ = 1.30cos25° = 1,18 km (neg. direction)

Cy= CsenФ = 1.30sen25° = 0.55 km (neg. direction)

Displacement D: 5.10 km due east (0°)

Dx= DcosФ = 5.10 km (pos. direction)

Dy= DsenФ = 0 km

Displacement E: 1.70 km and 5° east of north

Ex= EsenФ = 1.70sen5° = 0,15 km (pos. direction)

Ey= EcosФ = 1.70cos5° = 1.69 km (pos. direction)

Displacement F: 7.20 km and 55° south of west

Fx= FcosФ = 7.20cos55° = 4.13 km (neg. direction)

Fy= FsenФ = 7.20sen55° = 5.90 km (neg. direction)

Displacement G: 2.80 km and 10° north of east

Gx= GcosФ = 2.80cos10° = 2.76 km (pos. direction)

Gy= GsenФ = 2.80sen10° = 0.49 km (pos. direction)

Now, we add the components along the x- and y- axis to find the components of the resultant (R):

Rx = Ax + Bx + Cx + Dx + Ex + Fx + Gx

Ry = Ay + By + Cy + Dy + Ey + Fy + Gy

Therefore,

Rx= (-1.77)+(2.35)+(-1.18)+(5.10)+(0.15)+(-4.13)+(2.76)

Ry= (1.77)+(-4.07)+(-0.55)+(0)+(1.69)+(-5.90)+(0.49)

Note: minus (-) symbol to negative directions

Rx = 3.28 km

Ry = - 6.57 km

Let´s use the Theorem of Pythagoras to find the magnitud ot the resultant:

$R = \sqrt{Rx^{2} +Ry^{2} }$

$R =\sqrt{(3.28)^{2}+(-6.57)^{2} }$

R = 7,34 km

To find the direction of the resultant:

tanФ = $\frac{Ry}{Rx}$

tanФ = $\frac{6.57}{3.28}$

tanФ = 2.00

Ф = tan-1 (2.00)

Ф = 63,43° north of east

Download pdf

3 0

3 years ago

2. Circle C, has center (0,0) and radius 2.

adell [148]

Answer:

2. x ² + y ² = 4

3. x² + y² = 23

Step-by-step explanation:

The equation of a circle with center

( a , b ) and radius r is:

( x − a )² + ( y − b ) ² = r ²

Explanation:

Here,

a = 0 , b = 0 , r = 2

The equation is:

( x -0 ) ² + ( y -0 ) ² = ( 2 ) ²

that is: x ² + y ² = 4

Thus:

x ² + y ² = 4

3. Each point on a circle has the same distance from the center. This distance is the radius r of the circle.

Here, ( -3 , 4 ) is a point on the circle, meaning that the radius of the circle is the distance between ( 0 , 0 ) , the center, and ( -3 , 4 ) .

thus a circle centered on the origin will have an equation of:

x² + y² =r²

And, ( -3 , 4 ) lies on the circle, we have:

(-3)² + (4)² = r²

9 + 14 = 23

substituting;

x² + y² = 23

8 0

3 years ago