Question

Find the dot product of the position vectors whose terminal points are (8, 6) and (15, 8).

Answer 1

Dot product =  6*8 + 8*15
                   = 48 + 120
                    = 168

Answer 2

Answer:

Option D

Step-by-step explanation:

Given are two position vectors in two dimension.

They are (8,6) and (15,8)

We have to find the dot product.

We know that if

$a=a1i+a2j+a3k \\b = b1i+b2j+b3k\\a.b = a1b1+a2b2+a3b3$

Here two dimension

Hence dot product =$8(15)+6(8)\\= 8(21)\\= 168$

Option D is right