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2 years ago

A company manufactures 295 toy cars each day. How many toy cars do they manufacture in 34 days?

2 answers:

7 0

Simply, we know that in one day the company manufactures 295 cars, which can be expressed as an expression:
295 cars * 1 day = 295 cars per day

Therefor for 34 days we simply add 295 34 times as to equate to 295*34
Which gives us 10,030 cars

garik1379 [7]2 years ago

6 0

10,030 this is basic math you just have to multiple the amount the manufacture in one day by how many days you are measuring.

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rock is thrown upward with a velocity of 27 meters per second from the top of a 23 meter high cliff and it misses the cliff on t

ahrayia [7]

the rock will be at 11 meters from the ground level after 5.92 seconds

Step-by-step explanation:

The motion of the rock is a free-fall motion, since the rock is acted upon the force of gravity only. Therefore, it is a uniformly accelerated motion, so its position at time t is given by the equation:

$y=h+ut+\frac{1}{2}at^2$

where

h = 23 m is the initial height

u = 27 m/s is the initial velocity, upward

$a=g=-9.8 m/s^2$ is the acceleration of gravity, downward

t is the time

We want to find the time t at which the position of the rock is

y = 11 m

Substituting and re-arranging the equation, we find

$11=23+27t-4.9t^2\\4.9t^2-27t-12=0$

This is a second-order equation, which has solutions:

$t=\frac{27\pm \sqrt{(-27)^2-4(4.9)(-12)}}{2(4.9)}=\frac{27\pm \sqrt{964.2}}{9.8}$

$t_1 = -0.41 s$

$t_2=5.92 s$

The first solution is negative so we neglect it: therefore, the rock will be at 11 meters from the ground level after 5.92 seconds.

Learn more about free fall:

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#LearnwithBrainly

8 0

2 years ago

Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar

zavuch27 [327]

Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

$\bf \textit{hyperbolas, vertical traverse axis }
\\\\
\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h, k\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}\\
asymptotes\quad y= k\pm \cfrac{a}{b}(x- h)
\end{cases}\\\\
-------------------------------$

$\bf \begin{cases}
h=2\\
k=-3\\
a=6\\
c=2\sqrt{10}
\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2
\\\\\\
4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2
\\\\\\
\sqrt{4}=b\implies 2=b\\\\
-------------------------------\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1$

3 0

2 years ago

Sutract 5a -3b +2b from a-4b -2c

Alborosie

Step-by-step explanation:

-4a-5b-2c I think that is the best answer

8 0

2 years ago

Read 2 more answers

There are 8 cans of soup there are 3times as many cans of vegetables how many cans of vegetables are there write an equation to

kicyunya [14]

8(number of soup) times 3 =x (number of vegetable cans)

4 0

2 years ago

Read 2 more answers

Delaney would like to make a 5 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of peanuts and several

Alchen [17]

Answer:

a) The system that models the situation is:

p + 0.2m = 3

p + m = 5

b) The solution of the system is:

m = 2.5

p = 2.5

Step-by-step explanat:

It is desired to obtain 5 pounds of a mixture containing 40% peanuts and 60% almonds.

It has a mixture of 20% peanuts and 80% almonds.

p: number of pounds of peanuts

m = amount of mixture

The equation that represents the amount of peanut and mixture that is needed is:

p + m = 5 pounds

m = 5-p (i)

The amount of peanut in total that the mixture should have is:

p + 0.2m = 0.6 (5)

p + 0.2m = 3 (ii)

a) The system that models the situation is:

p + 0.2m = 3

p + m = 5

Now we substitute (i) in (ii) and clear p.

p + 0.2 (5-p) = 3

p-0.2p = 2

p = 2.5 pounds

Now we find m

m = 5 - 2.5

m = 2.5 pounds

b) The solution of the system is:

m = 2.5

p = 2.5

7 0

2 years ago