Question

Can someone answer this question for me? Thank you.

Answer 1

Answer:

$\boxed{\sf \ \ \ 3x^3-9x^2-30x=3x(x-5)(x+2) \ \ \ }$

Step-by-step explanation:

hello

step 1 - put 3x in factor

$3x^3-9x^2-30x=3x(x^2-3x-10)$

step 2 - factorise the quadratic form

product of zeros are -10 and the sum is 3, the roots are 5 and -2, as below

$x^2-3x-10=x^2+2x-5x-10=x(x+2)-5(x+2)=(x-5)(x+2)$

so the answer is

$3x^3-9x^2-30x=3x(x-5)(x+2)$

hope this helps