All categories

2 years ago

What is the solution to the equation below? Round your answer to two decimal places. e^x = 0.5

Mathematics

1 answer:

ASHA 777 [7]2 years ago

3 0

Answer:

x = -0.69

Step-by-step explanation:

We can get this by writing the equation in the logarithmic form to base e

We have this as;

log e 0.5 = x

x = ln 0.5

x = -0.69315

To two decimal places, this is -0.69

You might be interested in

Is number 4 right? please explain how you do these types of problems

Fantom [35]

Answer:

Step-by-step explanation:

I haven't learned this but my brother says its incorrect, he is in Highschool, though he doesn't use Brainly.

4 0

3 years ago

Read 2 more answers

Which of the following lists of network types appears in decreasing order of size?

Tju [1.3M]

WAN, LAN, PAN

Wide Area Network, Local Area Network, Personal Area Network

6 0

3 years ago

Read 2 more answers

If log2 5 = k, determine an expression for log32 5 in terms of k.

lukranit [14]

Answer:

$log_3_2(5)=\frac{1}{5} k$

Step-by-step explanation:

Let's start by using change of base property:

$log_b(x)=\frac{log_a(x)}{log_a(b)}$

So, for $log_2(5)$

$log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)$

Now, using change of base for $log_3_2(5)$

$log_3_2(5)=\frac{log(5)}{log(32)}$

You can express $32$ as:

$2^5$

Using reduction of power property:

$log_z(x^y)=ylog_z(x)$

$log(32)=log(2^5)=5log(2)$

Therefore:

$log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)$

As you can see the only difference between (1) and (2) is the coefficient $\frac{1}{5}$ :

So:

$\frac{log(5)}{log(2)} =k\\$

$log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k$

6 0

3 years ago

Plc help! Factor completely 2a^3b-ab^3-1 2/3ab^3-a^3b-4 1/2a^2b-1/2a^2b

alexandr402 [8]

Answer:

116−−√

110−−√

14√

18√

Step-by-step explanation:

7 0

2 years ago

On a number line, A is at -2 and B is at 4. What is the coordinate of C, which is 2/3

STatiana [176]

Answer:

Step-by-step explanation:

The distances have the ratio:

(C -A) = (2/3)(B -A)

C = (2/3)B +(1/3)A . . . . . add A

C = (2B +A)/3 . . . . . . . . combine terms

C = (2(4) +(-2))/3 = 6/3 = 2

The coordinate of C is 2.

7 0

3 years ago