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GaryK [48]
3 years ago
14

PLEASE ANSWER FAST

Mathematics
1 answer:
Setler [38]3 years ago
6 0
The length of all the sides is same, if u want to write it as an expression, you can write it as any variable, x,y or z
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Rob Polanski is a tractor salesman. Last week his total sales amounted to $38,642.00, and he received $2,704.94 in commission. W
pentagon [3]
2704.94 / 38642 = 0.07 = 7%
5 0
3 years ago
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Simplify each expression. Use positive exponents. <br> A^4b^-3<br> ab^-2
choli [55]
\dfrac{a^4b^{-3}}{ab^{-2}}

= {a^{4-1}b^{-3+2}}

= {a^{3}b^{-1}}

= \dfrac{a^3}{b}


6 0
3 years ago
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What percent of 78 is 16?
Phantasy [73]

Answer:

78/16=

39/8=

19.5/4= 4.80805

7 0
3 years ago
See image attached below keeeeeeeeeeeeeeeeeeeed
emmasim [6.3K]

Answer:

.13%

68.26%

2.28%

47.72%

49.87%

34.13%

Step-by-step explanation:

1.) standardize by subtracting the mean and dividng by the standard deviation

(625-1000)/125= -3

go to a ztable to get .0013 or (1-.9987)

this is equal to .13%

2.)

875<x<1125

standardize both seperately and subtract them

(875-1000)/125= -1  whose probability is .1587 (or 1-.8413)

(1125-1000)/125= 1  whose probability is .8413

.8413-.1587= 68.26%

3.)

Find the probability that someone paid less than 1250 and take its compliment

(1250-1000)/125= 2 which has a probability of .9772

take its compliment (1-.9772)= .0228= 2.28%

4.)

Same process as question 2

(750-1000)/125= -2 which has a probability of (1-.9772) = .0228

(1000-1000)/125= 0 which has a probability of .5

.5-.0228= .4772= 47.72%

5.) same deal as the previous question

(625-1000)/125= -3 which has a probability of (1-.9987)= .0013

(1000-1000)/125= 0 which has a probability of .5

.5-.0013= .4987= 49.87%

6.)same deal the previous question

(875-1000)/125= -1 which has a probability of (1-.8413)=.1587

(1000-1000)/125= 0 which has a probability of .5

.5-.1587= .3413= 34.13%

4 0
3 years ago
An item that originally cost $12 was on clearance Alford $3.60 what is the percentage of the discount
soldi70 [24.7K]

Answer:

she has hdu 7match the inequalities with the graphs

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3 years ago
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