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2 years ago

Solve for b. (b-7)m=r

Mathematics

1 answer:

deff fn [24]2 years ago

3 0

(b-7)m=r

Use the distributive property to multiply b-7 by m.

bm-7m=r

Add 7m to both sides.

bm=r+7m

The equation is in standard form.

mb=7m+r

Divide both sides by m.

mb/m = 7m+r/m

Dividing by m undoes the multiplication by m.

b= 7m+r/m

Divide r+7m by m.

b= r/m+7

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What is the product of the tens on 14 and 42

BartSMP [9]

Answer:

The product of the tens in these two numbers is 4

Step-by-step explanation:

TO find this, first we need to find the number in the tens place for each of them. The tens place is the second from the decimal point.

Now we take these two and multiply them together to get the product.

1 * 4 = 4

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3 years ago

Read 2 more answers

The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true

Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

Part A

$\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478$

Part B

$P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767$

Part C

$\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971$

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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saveliy_v [14]

Answer:

Step-by-step explanation:

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3 years ago

Quick pls

navik [9.2K]

First, let's see how 23 compares with the squares of the positive whole numbers on the number line.

1² = 1

2² = 4

3² = 9

4² = 16

5² = 25

The value of 23 is right between the square of 4 and the square of 5. Thus, the value √23 will be between 4 and 5.

Since 23 is much, much closer to the square of 5 than the square of 4, we can assume that the value √23 will be closer to 5 on the number line than 4.

Look at the attached image to see where I plotted the approximate location of √23.

You will realize that this approximation is pretty close since the actual value is roughly 4.80.

Let me know if you need any clarifications, thanks!

7 0

3 years ago