I assume there are some plus signs that aren't rendering for some reason, so that the plane should be

.
You're minimizing

subject to the constraint

. Note that

and

attain their extrema at the same values of

, so we'll be working with the squared distance to avoid working out some slightly more complicated partial derivatives later.
The Lagrangian is

Take your partial derivatives and set them equal to 0:

Adding the first three equations together yields

and plugging this into the first three equations, you find a critical point at

.
The squared distance is then

, which means the shortest distance must be

.
Answer:
1. x = 21
2. m∡ABC = 51°
Step-by-step explanation:
First problem, solve for x
the sum of inside angles of a triangle is 180
also the supplementary angle for L = 180 - 100 is 80°
now you can add all angles
80 + 2x - 11 + 2x + 27 = 180
4x + 96 = 180
4x = 84
x = 21
Second problem, solve for m∡ABC
the sum of inside angles of a triangle is 180
also the supplementary angle for C = 180 - 148 is 32°
now you can add all angles
31 + 2x - 15 + x - 5 = 180
3x + 12 = 180
3x = 168
x= 56,
now solve for m∡ABC = (x - 5)° = (56 - 5)° = 51°
Answer:
8
Step-by-step explanation:
Answer: y=8x-3
explanation:
y=mx+b
m= slope
b= y intercept
m=8 b=-3
y=8x-3
Answer:
His car would be worth $15,502.24
Step-by-step explanation:
20% of 17,500 is 350. 350 x 6 = 2,100. 17,500 - 2,100 = 15,400. But that is not an answer choice so be go to the closest number which is $15,502.24