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Kitty [74]
3 years ago
7

What is the unit rate of $4.20 for 6 muffins

Mathematics
1 answer:
Sergio [31]3 years ago
7 0
Well, you would divide 4.20/6 to find the price of just 1 muffin. 4.20/6 is 0.7, meaning that the price for one muffin is 70 cents.
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Estimate. Then find the difference 300,980 -159,000
Softa [21]

Answer:

142,000

Step-by-step explanation:

I would round 300,980 to the nearest thousands place = 301,000

Subtract 301,000 and 159,000 = 142,000

4 0
3 years ago
For the annual rate of change of +70%, find the corresponding growth or Decay Factor.
omeli [17]
Hello there!
1. Okay. So 70% is positive, so it is a corresponding growth. 70% is 0.7 in decimal form. C and D are both eliminated, because that's too large. When something grows by 70%, that is less than double. 0.7 is not right either, because that's more of a decay than a growth. The only answer that makes sense id 1.70, because you are going up, and adding 1 to decimal form brings you to the decimal that when multiplied will bring you to the total. The answer is B: 1.70.

2. So, -75% is negative, so it is a decay factor. A is eliminated, because it makes no sense and B is out, because that represents growth, not decay. You lose 75% of the amount overtime compounded, but you still have 25% that remains. To find that amount, you would subtract that amount from 1 to get the decay. 1 - 0.75 is 0.25. The decay factor is 0.25. The answer is D: 0.25.
4 0
3 years ago
Steve is making breakfast. The recipes call for 7/8 cup of milk for grits and 3/4 cups .for biscuits he only has 2 cups of milk.
Zanzabum
Answer: He does have enough.
Explanation: Simplifying 7/8 cups to fourths you get 1 3/4 cups of milk. If he has 2 cups of milk he still would have 1/4 cup left over of milk.
4 0
3 years ago
Helppppp❤️ Please please
kodGreya [7K]

Answer:

B and D

Step-by-step explanation:

I think this is the answer

7 0
2 years ago
Pls help I need this done asap
Paul [167]

Answer:

I can help you solve this.

but first telll me in the comments what is the formula for this equation and ill tell u from there

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