x=-6+2y
x=2+2y
by subtraction
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x=-8
Substitute x by one of the two equations :
x=-6+2y
-8=-6+2y
2y=-8+6
2y=-2
y=-2/2
y=-1
I think this is the answer
I hope I helped you^_^
Answer:
Step-by-step explanation:
We are told that n = 3m + 6. Substitutte 3m + 6 for n in the second equation, obtaining:
(3m + 6) - 2m = 2, or 3m + 6 - 2m = 2.
Combining like terms yields
m = -4.
Knowing that m = -4 allows us to calculate n. Use the first equation, n = 3m + 6, for this purpose: n = 3(2) + 6 = 12.
Thus, the solution is (2, 12).
The equation of a circle is:
(x-h)^2 + (y-k)^2 = r^2
where (h,k) is the location of the center and r is the radius. So we need to find h, k, and r. The center is given as (5,-4) so h = 5 and k = -4:
(x-5)^2 + (y-(-4))^2 = r^2
(x-5)^2 + (y+4)^2 = r^2
So we need to find r. Use the distance formula to find the distance between (5,-4) and (-3,2):
r = [(5-(-3))^2+((-4)-2)^2]^1/2
r = [8^2 + (-6)^2]^1/2
r = [64 + 36]^1/2
r = 100^1/2
r= 10
The final equation is:
(x-5)^2 + (y+4)^2 = 10^2
If the bold numbers and variables are 2x + 5, then those would be B. addend, or the numbers that are added. Minuend is the number from which you subtract.
And since there is no dividing here, C or D are incorrect.
