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2 years ago

9

A garbabge cn shape like a rectangular prism the lenght is 8 feet the width is 4 feet and the height is five feet what is the vo

lume

1 answer:

V125BC [204]2 years ago

8 0

Answer:

160 feet³

Step-by-step explanation:

Volume of a rectangular prism = length x breadth x height

8 feet x 4 feet x 5 feet = 160 feet³

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What is the system of inequalities associated with the following graph?

slamgirl [31]

One line passes through the points (-2,3) and (0,-3) , it means the y intercept is b=-3

and slope m = $\frac{(-3-3)}{0-(-2)}$

$= \frac{-6}{2}= -3$

So the equation of line will be $y= -3x -3$

And the inequality should be $y\geq -3x-3$

Or $3x +y \geq -3$

And the other line passes through (-2,3) and (0,2)

So the y intercept is b=2

and the slope is $m= \frac{2-3}{0-(-2)} = \frac{-1}{2}$

So the equation of line will be $y= \frac{-1}{2} x +2\\and the inequality should be y \leq \frac{-1}{2} x+2$

Or

$2y +x \leq 4$

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3 years ago

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Kelly needs to order lunch for orders 6 people at a business meeting. Her menu choices are chicken salad for a cost of $5 per pe

nirvana33 [79]

Ok , with that information we can write the equations
x + y = 6
5x + 4y = 28

Where x = how many people ordered chicken
and y = how many people ordered egg salad

Through elimination , we can set one of the variables in both equations equal so we can eliminate it :

(4)x + (4)y = (4)6
5x + 4y = 28

4x + 4y = 24. equation 1
5x + 4y = 28. equation 2

Now we can subtract the second equation by the first equation and isolate one variable:
equation 2 - equation 1

5x - 4x + 4y - 4y = 28 - 24

x = 4

Now that we discovered our x value ( How many people ordered chicken salad ) , we can apply it to one of the equations and discover y ( how many people ordered egg salad)

x + y = 6
x= 4
4 + y = 6

We can shift 4 to the other side of the equation by subtracting 4 from both sides of the equation:
4 - 4 + y = 6 - 4
y = 2

x=4 and y=2

So the awnser is :
4 people ordered chicken salad and 2 people ordered egg salad!

I hope you understood my brief explanation!!

p.s if you want to know how to use another method to solve these problems ( Substition) , just let me know in a comentary down here

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Rufina [12.5K]

I believe its exponent

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2 years ago

A tank contains 1600 L of pure water. Solution that contains 0.04 kg of sugar per liter enters the tank at the rate 2 L/min, and

goldfiish [28.3K]

Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of

(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min

and flows out at a rate of

(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min

Then the net flow rate is governed by the differential equation

$\dfrac{\mathrm dS(t)}{\mathrm dt}=\dfrac8{100}-\dfrac{S(t)}{800}$

Solve for S(t):

$\dfrac{\mathrm dS(t)}{\mathrm dt}+\dfrac{S(t)}{800}=\dfrac8{100}$

$e^{t/800}\dfrac{\mathrm dS(t)}{\mathrm dt}+\dfrac{e^{t/800}}{800}S(t)=\dfrac8{100}e^{t/800}$

The left side is the derivative of a product:

$\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/800}S(t)\right]=\dfrac8{100}e^{t/800}$

Integrate both sides:

$e^{t/800}S(t)=\displaystyle\frac8{100}\int e^{t/800}\,\mathrm dt$

$e^{t/800}S(t)=64e^{t/800}+C$

$S(t)=64+Ce^{-t/800}$

There's no sugar in the water at the start, so (a) S(0) = 0, which gives

$0=64+C\impleis C=-64$

and so (b) the amount of sugar in the tank at time t is

$S(t)=64\left(1-e^{-t/800}\right)$

As $t\to\infty$ , the exponential term vanishes and (c) the tank will eventually contain 64 kg of sugar.

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Examples of repeating decimals

Aliun [14]

6.66, with a bar on top of the last two sixes

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