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Flura [38]
3 years ago
9

Please help me with this.

Mathematics
1 answer:
-Dominant- [34]3 years ago
5 0

Answer:

3

Step-by-step explanation:

Parenthesis

Exponents

Multiplication

Division

Addition

Subtraction

3^4 +9^2÷3^3-9^2

81+81÷27-81

81+3-81

3

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Can I get an example of systems of equations that represent the solution of this situation below? (It doesn't need to be solved.
solong [7]

Answer:

x + y = 11

10x + 5y = 80

Step-by-step explanation:

6 0
2 years ago
Help please now i cant figure it out
12345 [234]

Answer:

a. \frac{-11}{24}

b. \frac{-3}{2} \\

c. \frac{31}{7}

d.  \frac{11}{16}

11, 3, 31, 11 = code

Step-by-step explanation:

a. \frac{-1}{6}\\ * 2\frac{3}{4} =

2\frac{3}{4} = \frac{4*2+3 }{4}=  \frac{11}{4}

\frac{-1}{6}\\ * \frac{11}{4} = \frac{-1*11}{6*4} = \frac{-11}{24}

b.  \frac{3}{16} / \frac{-1}{8} =

\frac{3}{16} * \frac{8}{-1} = \frac{3*8}{16*-1} \\ = \frac{24}{-16} = \frac{-3}{2} \\

c. \frac{-31}{56} * \frac{-8}{1} = \frac{31}{7} (you can reduce 8 & 56 by dividing by 8: 56/8=7 & -8/8= -1)

d. 1 \frac{7}{8} / 2\frac{8}{11} =

1 \frac{7}{8} = \frac{8*1+7}{8} = \frac{15}{8}

2\frac{8}{11} = \frac{11*2+8}{11} = \frac{30}{11}

\frac{15}{8} * \frac{11}{30} = \frac{11}{16} (you can reduce 15 & 30 by dividing by 15: 15/15=1 & 30/15 = 2)

4 0
2 years ago
How would I put this equation into standard form for a parabola?
Bezzdna [24]

Answer:

fffffffffffffffffffffffffffffff

Step-by-step explanation:


5 0
2 years ago
Number 3 plzzzzzzzzz
zhenek [66]

Answer:

A

Step-by-step explanation:

I'm pretty sure some smart guy in Greece noticed this but:

Since 4 + 8 = 12, thats the only option where 2 of the smaller sides add up to the big one. I don't know much of the reasoning behind this but my math teacher showed it to us by using Popsicle sticks to make triangles. You can try it if that helps you think about it. Apparently, if you add up the 2 smaller sides, then it HAS to be more than the biggest side.

5 0
2 years ago
Read 2 more answers
Find the volume of the solid formed by rotating the region bounded by the given curves about the indicated axis. Y = 1x, y = 1,
Goryan [66]

The disk method will only involve a single integral. I've attached a sketch of the bounded region (in red) and one such disk made by revolving it around the y-axis.

Such a disk has radius x = 1/y and height/thickness ∆y, so that the volume of one such disk is

π (radius) (height) = π (1/y)² ∆y = π/y² ∆y

and the volume of a stack of n such disks is

\displaystyle V_n = \sum_{i=1}^n \pi {y_i}^2 \Delta y

where y_i is a point sampled from the interval [1, 5].

As we refine the solid by adding increasingly more, increasingly thinner disks, so that ∆y converges to 0, the sum converges to a definite integral that gives the exact volume V,

\displaystyle V = \lim_{n\to\infty} V_n = \int_1^5 \frac{\pi}{y^2} \, dy

V = -\dfrac\pi y\bigg|_{y=1}^{y=5} = \boxed{\dfrac{4\pi}5}

8 0
1 year ago
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