Answer:
3x^4-18x^3+27x^2-12x
Step-by-step explanation:
Multiply the second paréntesis for each term of the first parentage
3x^2×(x^2-2x+1)-12x×(x^2-2x+1)
Multiply parentage by 3x^2
3x^4-6x^3+3x^2-12x×(x^2-2x+1)
Multiply the parentage by -12x
3x^4-6x^3+3x^2-12x^3+24x^2-12x
Group similar terms
3x^4-18x^3+27x^2-12x
Answer: No more than 8.8 pounds.
Step-by-step explanation: Let x be the weight that Lorrie can add to carry-on.
We are told that an airline charges an extra fee if a carry-on bag weighs more than 30 pounds. After packing, Lorrie’s carry-on weighs 21.2 pounds. The inequality that will represent the the amount of weight Lorrie can add to the carry-on without going over the 30-pound limit is:
Let us solve for x by subtracting 21.2 from both sides of our inequality.
We can see that the weight Lorrie can add to the carry-on should be less than or equal to 8.8 pounds without going over the 30 pound limit. Therefore, the weight that Lorrie can add to the carry-on should be no more than 8.8 pounds.
Answer:
Step-by-step explanation:
2
Order least to greatest -3/4 , -2/3 ,1/2
