This is the same as showing the following system of equations doesn't have a solution:
or in matrix form,
The quickest way to check if there is a solution is to check whether the coefficient matrix is invertible. If its determinant is 0, then it is not invertible.
And the quickest way to show that the determinant is 0 is by observing that the third row is a linear combination of the first two rows:
(-2, 9, 6) - (-3, 2, 1) = (-2 + 3, 9 - 2, 6 - 1) = (1, 7, 5)
So there are indeed no such scalars <em>c₁</em>, <em>c₂</em>, and <em>c₃</em>.
Answer:
Christopher is 24 years old now
Step-by-step explanation:
I honestly don't know how I got my answer but I know it's correct
Answer:
D
Step-by-step explanation:
rule: Diametre includes the centre of a circle.
According to the given conditions AB and DE are diameters.
Answer: OPTION C
Step-by-step explanation:
To solve the exercise shown in the image attached, you need to subtract the functions f(x) and g(x).
Keeping the above on mind, you have:
You must distribute the negative sign and then you must add the like terms, therefore, you obtain:
Your answer is 76m.
a^2+b^2=c^2
57^2+b^2=95^2
3249+b^2=9025
b^2=5776
Take sqr on both sides and you get:
b=76m
