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UNO [17]
3 years ago
8

The wheels on Jason’s dirt bike measure 19 inches in diameter. How many revolutions will the wheels make when Jason rides for 50

0 feet? Use 3.14 for π. Round to the nearest whole revolution. A. 8 revolutions B. 21 revolutions C. 101 revolutions D. 316 revolutions
Mathematics
1 answer:
jek_recluse [69]3 years ago
8 0

Answer:

C. 101 revolutions

Step-by-step explanation:

The wheels on Jason’s dirt bike measure 19 inches in diameter. Using 3.14 for π, if Jason rides for 500 feet, the wheels will make 101 revolutions.

3.14 ⋅ 19 inches = 3.14 ⋅ ¹⁹/¹² = 4.97 feet or 101 revolutions

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Express 6^1/4 b^3/4 c^1/4 using a radical
hodyreva [135]

Answer:

B

Step-by-step explanation:

6^{\frac{1}{4} } b^{\frac{3}{4} }c^{\frac{1}{4} }\\\\=(6^1b^3c^1)^{\frac{1}{4} }\\\\=(6b^3c)^\frac{1}{4} \\\\=\sqrt[4]{6b^3c}

so answer is B

8 0
3 years ago
Find the side lengths of each triangle ​
Levart [38]

Answer:

Step-by-step explanation:

So add the numbers on each side together

7 0
2 years ago
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nevsk [136]

Answer:

b

Step-by-step explanation:

I hope this helps and have a nice day

5 0
3 years ago
Read 2 more answers
An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s
Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, s=120\ ft/s

The height 'h' of the debris above the ground is given as:

h(t)=-16t^2+120t

As per question, h(t)=56\ ft. Therefore,

56=-16t^2+120t

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0

Using quadratic formula to solve for 't', we get:

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s

Therefore, the debris will reach a height of 56 ft twice.

When time t=0.5\ s during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at t=7\ s, the height is 56 ft.

5 0
3 years ago
Use the discriminant to determine the nature of the roots of the following equation.
kvv77 [185]

Discussion

The discriminate is b^2 - 4*a*c

The general equation for a quadratic is ax^2 + bx + c

In this equation's case

a = 1

b= -5

c = - 3

Solve

(-5)^2 - 4*(1)*(-3)

25 - (-12)

25 + 12

37

Note

Since the discriminate is > 0, the roots are real and different. The roots do exist and there are 2 of them.

4 0
3 years ago
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