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suter [353]
2 years ago
8

You are selling raffle tickets to raise money. Each ticket costs $5. Which equation solves for the number of tickets you must se

ll to raise $45?
A) 45-5=x
B) x/4=45
C) 45=5+x
D) 5x=45
Mathematics
1 answer:
aleksley [76]2 years ago
8 0

D. 5x = 45 because you are trying to find x, the number of tickets that must be sold to earn $45.

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What is the fraction for five over two
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Answer:

So normally you would say it as

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<em>(2 1/2)</em>

<em></em>

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3 0
3 years ago
Expand (2+x)^-3<br><br><br><br><br><br><br><br> ....
pentagon [3]

Answer:

1/(x^3 + 6x^2 + 12x + 8)

Step-by-step explanation:

The first thing we do is rationalize this expression. (2+x)^-3 is written as

1/(2+x)^3

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(2+x)(2+x) = 4 + 4x + x^2

(4+4x+x^2)(2+x) = 8+8x+2x^2+4x+4x^2+x^3.

Then we combine like terms and put them in order to get:

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6 0
2 years ago
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Gwen bought 3 sodas at the grocery store if each soda cost $1.85 and she paid with a twenty dollar bill how much change should s
AnnZ [28]

Answer:

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Step-by-step explanation:

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3 0
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Answer:

Step-by-step explanation:

LHS = Sin² ∅ + Sin² ∅*tan² ∅

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         = Sin² ∅ *Sec² ∅

         = Sin² ∅ * \frac{1}{Cos^{2} }

         = Sin² ∅ /Cos² ∅

        =  tan² ∅  = RHS

8 0
3 years ago
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ivolga24 [154]

Answer:

$4020.52

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The future value is the principal multiplied by the amount $1.00 is worth in the future.

$4,000 × 1.00513 = $4020.52

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