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cluponka [151]
3 years ago
6

Which series of transformations would transform triangle A into similar triangle A' in Quadrant IV? A. Rotate triangle A 90 cloc

kwise about the origin then translate five units up B. Dilate triangle A by a scale factor of 4. Translate triangle A to the left. C. Reflect triangle A across the y-axis and then translate the triangle 3 units up and 2 units to the right. D. Reflect triangle A across the x-axis and then reflect the triangle across the y-axis.

Mathematics
1 answer:
VikaD [51]3 years ago
6 0

Answer:

<u>option D</u>

Step-by-step explanation:

It is required to transform triangle A into similar triangle A' in Quadrant IV.

The given triangle in Quadrant II.

We will check the options:

A. Rotate triangle A 90 clockwise about the origin then translate five units up.

Wrong because  triangle A' will be at Quadrant I.

B. Dilate triangle A by a scale factor of 4. Translate triangle A to the left.

Wrong because  triangle A' will be at Quadrant II.

C. Reflect triangle A across the y-axis and then translate the triangle 3 units up and 2 units to the right.

Wrong because  triangle A' will be at Quadrant I.

D. Reflect triangle A across the x-axis and then reflect the triangle across the y-axis.

True Because reflection triangle A across the x-axis, the first image will be at  Quadrant III, then reflection the first image across the y-axis, we will get triangle A' will be at Quadrant IV.

<u>So, the answer is option D</u>

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Find the distance between (-5,6)and (3,2).
skad [1K]

Answer:

\displaystyle d = 4\sqrt{5}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-5, 6) → x₁ = -5, y₁ = 6

Point (3, 2) → x₂ = 3, y₂ = 2

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formulas]:                                                     \displaystyle d = \sqrt{(3+5)^2+(2-6)^2}
  2. [Distance] [√Radical] (Parenthesis) Add/Subtract:                                       \displaystyle d = \sqrt{(8)^2+(-4)^2}
  3. [Distance] [√Radical] Evaluate exponents:                                                    \displaystyle d = \sqrt{64+16}
  4. [Distance] [√Radical] Add:                                                                             \displaystyle d = \sqrt{80}
  5. [Distance] [√Radical] Simplify:                                                                         \displaystyle d = 4\sqrt{5}
6 0
3 years ago
Convert the measurement as indicated.<br><br> 26ft= _ yd _ ft
Yakvenalex [24]
26ft(yd/3ft)

8yd+2yd/3

8yd+(2yd/3)(3ft/yd)

8yd+2ft

8yd 2ft
5 0
3 years ago
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I NEED THIS ANSWER FAST. Show work.
777dan777 [17]

Answer:

1/20

Step-by-step explanation:

Entire the entire bottle/tube of the treatment.

3 0
4 years ago
Solve for X. First to answer is marked branliest.
Bas_tet [7]

Answer:

Step-by-step explanation:

Solution

Here,

h²=p²+b²

or,15²=x²+7²

or,225=x²+49

or,x²=225-49

or,x²=176

x=13.266

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8 0
3 years ago
1.2.71
egoroff_w [7]

Answer:

Step-by-step explanation:

Set up an equation, where x is the number of gallons of 60% antifreeze solution.

Represent the percentages of antifreeze with decimal values.

0.6x + 0.3(80) = 0.5(x + 80)

Simplify and solve for x:

0.6x + 24 = 0.5x + 40

0.1x = 16

x = 160

So, you have to mix 160 gallons of a 60% antifreeze solution

6 0
3 years ago
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