The addtive inverse of the complex number (4_7)

Mathematics

1 answer:

Nady [450]3 years ago

6 0

ANSWER

My answer is in the photo above

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Pls help me to find IK!

docker41 [41]

Answer:

Step-by-step explanation:

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49-19=30

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47.5%

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X - y = 3<br> x + 3y = 9

Ugo [173]

Solve for one of the variables in the first equation (in this case, I will solve for X):
X = Y + 3

Then use that value of X in the second equation to solve for Y:
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Use the value of Y we just found in the X equation we created:
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Which of the following would be an acceptable first step in simplifying the expression sinx/1-sinx

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$\bf \textit{difference of squares}
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(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
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\textit{also recall that }sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
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$\bf \cfrac{sin(x)}{1-sin(x)}\implies \cfrac{sin(x)}{1-sin(x)}\cdot \cfrac{1+sin(x)}{1+sin(x)}\implies \stackrel{first~step}{\cfrac{sin(x)[1+sin(x)]}{[1-sin(x)][1+sin(x)]}}
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tan(x)[sec(x)+tan(x)]$

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3 years ago

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