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Leokris [45]
2 years ago
9

I am having trouble with this problem....

Mathematics
1 answer:
Alexeev081 [22]2 years ago
4 0

There 2 angles are corresponding angles, in which the angle measurements would have the same degree.

Set the two angles equal to each other, and solve for x.

7x - 1 = 8x - 14

Isolate the x. Subtract 8x from both sides, and add 1 to both sides

7x (-8x) - 1 (+1) = -14 (+1)

7x - 8x = -14 + 1

-x = -13

Isolate the x. Divide -1 from both sides

(-x)/-1 = (-13)/-1

x = -13/-1

x = 13

13 is your answer for x.

~

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Find the area of the region in two ways. a. Using integration with respect to x. b. Using geometry. 9-x
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Answer: hello your question is incomplete attached below is the complete question

answer :

a)   \int\limits^3_0 {(10-x)-(x+4)} \, dx     ( option D )

b) A =  1/2 (6)(3)   ( option B )

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Step-by-step explanation:

<u>a) Using integration with respect to x </u>

Area =   \int\limits^7_4 {(y-4)} \, dy + \int\limits^a_7 {(10-y)} \, dy         ( note a = 10 )

          = y^2/2 - 4y |⁷₄  + 10y - y^2/2 |¹⁰₇

          = 33/2 - 12 + 30 - 51/2   = 9

hence the best integral from the options attached is option D

\int\limits^3_0 {(10-x)-(x+4)} \, dx

= [ 10x - x^2 /2 - x^2/2 - 9x ] ³₀

= 30 - 9/2 - 9/2 - 12  = 9

<u>b) Using Geometry </u>

Area = 1/2 * base * height

        = 1/2 * 6 * 3

        = 9

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