A=(6.25h)+(6b)
total = hrs worked times hourly pay + number of memberships sold times what she gets from it
The number of student tickets sold is half the total plus half the difference:
student tickets = (603 +53)/2 = 656/2 = 328
The number of adult tickets is 53 fewer, 275.
Answer:
1.4000 ;
0.0807 ;
1.69 ;
Fail to reject the Null
Step-by-step explanation:
Given :
μ = 21 minutes
x = 22.4 minutes
Sample size, n = 36
Standard deviation, s = 6
H0: μ ≥ 21
H1: μ < 21
Test statistic : (x - μ) ÷ s/sqrt(n)
Test statistic : (22.4 - 21) ÷ 6/sqrt(36)
Test statistic : 1.4 ÷ 1
Test statistic = 1.4000
Pvalue : Using the Test statistic value at α = 0.05 ; One - tail test = 0.0807
The t critical value using a critical value calculator ; DF = (n - 1) = 36 - 1 = 35 ; α = 0.05 = 1.69
Decision region :
Reject H0 if
|Test statistic| > |critical value|
1.4 < 1.69
Hence, we fail to reject H0
There isn't enough evidence they delivery time has been reduced below previous mean
Answer: (100th answer)
perimeter of field b = 260 m
Step-by-step explanation:
First we have to find what is 7/12 of 108?
Well first we need to know what 1/12 of 108 is. Which means we do 108/12. That equals 9. so if 1/12 of 108 = 9
then 7/12 of 108 is 9*7 which is 63.
The width of field A is 63 plus its length, width again and its length again would be its perimeter or
2l + 2w is its perimeter, where l is length and w is width
108*2+63*2= perimeter
216+126 = ?
342 is the perimeter of field A.
We aren't done though.
We have to find 5/6 of 342.
1/6 of 342 is 342/6
342/6 = 52
1/6 of 342 = 52 meaning 5/6 of 342 is equal to 5*52.
5*52 = 260
the perimeter of field b is 260
