1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
makvit [3.9K]
3 years ago
5

The rate of the jet stream is 100 miles per hour. Traveling with the jet​ stream, an airplane can fly 1200 miles in the same amo

unt of time as it takes to fly 1000 miles against the jet stream. What is the​ airplane's average rate in calm​ air?
Mathematics
1 answer:
irga5000 [103]3 years ago
5 0

Answer:

x = 600 mph

Step-by-step explanation:

It is given that,

Speed of the jet stream = 100 mph

It travels 1200 miles in the same amount of time as it takes to fly 1000 miles against the jet stream.

We need to find the airplane's average rate in calm​ air. Let it is equal to x mph.

As time in same in both cases. ATQ,

\dfrac{1200}{x}=\dfrac{1000}{x-100}\\\\\dfrac{12}{x}=\dfrac{10}{x-100}\\\\12x-1200=10x\\\\12x-10x=1200\\\\2x=1200\\\\x=600

So, the airplane's average rate in calm​ air is 600 mph. Hence, this is the required solution.

You might be interested in
The North building of the World Trade
kiruha [24]
The answer is C. 400
5 0
3 years ago
Evaluate the expression when a=-7. a^2+4a-2
andrey2020 [161]

Plug in the value to solve the expression.

(-7)^2+4(-7)-2

49-28-2

19

Hope this helps.

頑張って!

4 0
4 years ago
How do I solve this?
Verdich [7]

Consider the point P where the gears meet. When the smaller gear rotates clockwise, the larger one will rotate counterclockwise.

Through one rotation of the smaller gear, P will have traveled the circumference of the smaller gear, which is 8\pi in.

At the same time, a point P' on the larger gear traverses the same distance along the larger gear's circumference. This point traces out an arc that is subtended by some angle \theta. The arc is as long as the smaller gear's circumference.

The measure of a circle's interior angle subtended by an arc is proportional to a complete revolution, i.e. an angular displacement of 2\pi radians:

\dfrac{14\pi\,\mathrm{in}}{2\pi\,\mathrm{rad}}=\dfrac{8\pi\,\mathrm{in}}\theta\implies\theta=\dfrac{8\pi}7\,\mathrm{rad}\approx205.7^\circ

For part 2, we apply the same reasoning to the larger gear. In one full rotation of the larger gear, the point P' traverses the circumference 14\pi in, and so does the point P on the smaller gear.

\dfrac{8\pi\,\mathrm{in}}{2\pi\,\mathrm{rad}}=\dfrac{14\pi\,\mathrm{in}}\theta\implies\theta=\dfrac{7\pi}2\,\mathrm{rad}=630^\circ

A full rotation is 360 degrees, so the smaller gear would have rotated \dfrac{630^\circ}{360^\circ}=1.75 times.

6 0
3 years ago
The total square footage of wall space to be painted is 300 square feet. If a gallon of paint covers 240 square feet, how many q
UNO [17]

Answer:

You will need 5 quarts of paint to cover 300 square paint

Step-by-step explanation:

7 0
3 years ago
If k(x) = 5x – 6, which expression is equivalent to (k + k)(4)?
borishaifa [10]
(k + k)(4) =
5x - 6 + 5x - 6 = 10x - 12 =
10(4) - 12 = 40 - 12 = 28
The answer is 28
7 0
3 years ago
Read 2 more answers
Other questions:
  • What is 4+2 x { 16/ (5+3)} 2
    6·2 answers
  • Find the missing side length??????
    8·1 answer
  • When segments intersect inside a circle, what is the relationship between the angle of intersection and the intercepted arcs?
    11·2 answers
  • The distance a car can travel on a certain amount of fuel varies inversely with its speed. If a car traveling 50 mph can travel
    9·2 answers
  • Please help me with my maths question​
    7·1 answer
  • Someone please help !! i’m strugglingg
    6·1 answer
  • Write the equation of the graph.
    9·1 answer
  • Find the value of x so that the function has the given value:
    11·1 answer
  • The fall of berlin wall​
    13·1 answer
  • Random photo dump.........<br> I'm the one With the pink gun holder thingy
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!