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makvit [3.9K]
3 years ago
5

The rate of the jet stream is 100 miles per hour. Traveling with the jet​ stream, an airplane can fly 1200 miles in the same amo

unt of time as it takes to fly 1000 miles against the jet stream. What is the​ airplane's average rate in calm​ air?
Mathematics
1 answer:
irga5000 [103]3 years ago
5 0

Answer:

x = 600 mph

Step-by-step explanation:

It is given that,

Speed of the jet stream = 100 mph

It travels 1200 miles in the same amount of time as it takes to fly 1000 miles against the jet stream.

We need to find the airplane's average rate in calm​ air. Let it is equal to x mph.

As time in same in both cases. ATQ,

\dfrac{1200}{x}=\dfrac{1000}{x-100}\\\\\dfrac{12}{x}=\dfrac{10}{x-100}\\\\12x-1200=10x\\\\12x-10x=1200\\\\2x=1200\\\\x=600

So, the airplane's average rate in calm​ air is 600 mph. Hence, this is the required solution.

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A rectangle has an area of 1/6 square centimeters and a length of 1.5 centimeters. what is the width? what is the perimeter?
SCORPION-xisa [38]
The area of a rectangle can be calculated by the product of its length and the width. Here we are given the area and the length so we can simply calculate for width. The perimeter is the sum of all the side lengths of the shape. We calculate as follows:

Area = lxw
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Perimeter = 2l + 2w
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Hope this answers the question. Have a nice day.
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The probability that the random variable X takes the value x is given by P(X=x) = 25Cx 0.05^x0.95^{25-x}. Then,

(a) P(X\leq) = (25C0)(0.05^0)(0.95^{25}) + (25C1)(0.05^1)(0.95^{24}) + (25C2)(0.05^2)(0.95^{23})=  0.873

(b) P(X\geq5) = 1-P(X\leq4) = 1 - (0.873 + (25C3)(0.05^3)(0.95^{22}) + (25C4)(0.05^4)(0.95^{21})) = 1 - (0.873 + 0.12) = 0.007

(c) P(1\leqX\leq4) = (25C1)(0.05^1)(0.95^{24}) + (25C2)(0.05^2)(0.95^{23}) + (25C3)(0.05^3)(0.95^{22}) + (25C4)(0.05^4)(0.95^{21}) = 0.715

(d) P(X=0) = (25C0)(0.05^0)(0.95^{25}) = 0.277  

(e) E(X) = np = (25)(0.05) = 1.25 and Sd(X) = \sqrt{Var(X)} = \sqrt{np(1-p)} = 1.09

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Look at the whole numbers. Is there a number that divides into them evenly? Yes, 2, so you pull 2 from the problem and divide each number by 2. Do the same for each variable.

2a2b3 - 14ab + 16a

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